JonnyF--Compare Version Numbers

Compare two version numbers version1 and version2.
If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.

You may assume that the version strings are non-empty and contain only digits and the . character.
The . character does not represent a decimal point and is used to separate number sequences.
For instance, 2.5 is not "two and a half" or "half way to version three", it is the fifth second-level revision of the second first-level revision.

Here is an example of version numbers ordering:

0.1 < 1.1 < 1.2 < 13.37

解题思路：

      这道题从字面上就可以看出来，其实是求不同版本号直接大小的。

class Solution:
    # @param version1, a string
    # @param version2, a string
    # @return an integer
    def compareVersion(self, version1, version2):
        ver1 = version1.split('.')
        ver2 = version2.split('.')
        len1 = len(ver1)
        len2 = len(ver2)
        Maxv = max(len1, len2)
        for i in range(Maxv):
            v1 = 0
            if i < len1:
                v1 = int(ver1[i])
            v2 = 0
            if i < len2:
                v2 = int(ver2[i])
            if v1 > v2:
                return 1
            if v1 < v2:
                return -1
        return 0