K倍动态减法游戏

题目:http://acm.hdu.edu.cn/showproblem.php?pid=2580


 

#include <iostream>
#include <string.h>
#include <stdio.h>

using namespace std;
const int N = 2000005;

int a[N],b[N];

int main()
{
    int T,tt=1;
    int n,k;
    scanf("%d",&T);
    while(T--)
    {
        scanf("%d%d",&n,&k);
        a[0] = b[0] = 1;
        int i = 0;
        int j = 0;
        while(a[i] < n)
        {
            i++;
            a[i] = b[i-1] + 1;
            while(a[j+1] * k < a[i]) j++;
            if(a[j] * k < a[i]) b[i] = a[i] + b[j];
            else b[i] = a[i];
        }
        printf("Case %d: ",tt++);
        if(a[i] == n) puts("lose");
        else
        {
            int ans = 0;
            while(n)
            {
                if(n >= a[i])
                {
                    n -= a[i];
                    ans = a[i];
                }
                i--;
            }
            printf("%d\n",ans);
        }
    }
    return 0;
}


 

题目:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=3599


 

#include <iostream>
#include <string.h>
#include <stdio.h>

using namespace std;
typedef long long LL;
const LL N = 3000005;

LL a[N],b[N];

int main()
{
    LL T;
    LL n,k;
    scanf("%lld",&T);
    while(T--)
    {
        scanf("%lld%lld",&k,&n);
        a[0] = b[0] = 1;
        LL i = 0;
        LL j = 0;
        while(a[i] < n)
        {
            i++;
            a[i] = b[i-1] + 1;
            while(a[j+1] * k < a[i]) j++;
            if(a[j] * k < a[i]) b[i] = a[i] + b[j];
            else b[i] = a[i];
        }
        LL ans = 0;
        if(a[i] == n) ans = n - i - 1;
        else ans = n - i;
        printf("%lld\n",ans);
    }
    return 0;
}


 


 

posted on 2013-12-03 10:08  我的小人生  阅读(327)  评论(0编辑  收藏  举报