MySql 实现数据排名各版本总结

 

一、MySql 8.0 以下 实现排名


--
方法一
SELECT name, score, @rank := @rank + 1 as pm FROM scores A, (SELECT @rank := 0) B ORDER BY score DESC; -- 方法二 select C.* from ( SELECT A.*, @rank := @rank + 1 as pm FROM ( SELECT name, score FROM scores ORDER BY score DESC ) A, (SELECT @rank := 0) B ) as C; -- 方法三 select B.*, @curBank := IF(@prevRank = B.score, @curBank, @incRank) as 'pm', @incRank := @incRank + 1 as 'inc', @prevRank := B.score as 'sc' from ( select name, score from scores A, (select @curBank := 0, @prevRank := null, @incRank := 1) r group by name ) as B order by B.score desc; -- 方法四 select B.*, @curBank := IF(@prevRank = B.score, @curBank, @incRank) as 'pm', @incRank := @curBank + 1 as 'inc', @prevRank := B.score as 'sc' from ( select name, score from scores A, (select @curBank := 0, @prevRank := null, @incRank := 1) r group by name ) as B order by B.score desc;
        

 

结果一(方法一、方法二):

   

 

 

结果二(方法三):

   

 

结果三(方法四):

    

 

 

二、MySql 8.0 实现排名

 

函数作用
RANK 并列跳跃排名,并列即相同的值,相同的值保留重复名次,遇到下一个不同值时,跳跃到总共的排名。
DENSE_RANK 并列连续排序,并列即相同的值,相同的值保留重复名次,遇到下一个不同值时,依然按照连续数字排名。
ROW_NUMBER 连续排名,即使相同的值,依旧按照连续数字进行排名。

  


--
方法一 select name,score, rank() over(ORDER BY score desc) as 'pm' from scores; -- 方法二 select name,score, dense_rank() over(ORDER BY score desc) as 'pm' from scores; -- 方法三 select name,score, row_number() over(ORDER BY score desc) as 'pm' from scores;

 

结果一:

   

 

  

结果二:

   

 

 

结果三:  

   

 

posted @ 2021-11-03 13:56  追太阳的小码妹  阅读(1071)  评论(0编辑  收藏  举报