leetcode@ [84/85] Largest Rectangle in Histogram & Maximal Rectangle

https://leetcode.com/problems/largest-rectangle-in-histogram/

https://leetcode.com/problems/maximal-rectangle/

 1 class Solution {
 2 public:
 3     int largestRectangleArea2(vector<int> height) {
 4         if(height.size()==0) return 0;
 5         
 6         int ret = numeric_limits<int>::min();
 7         for(int i=0;i<height.size();++i) {
 8             int area = height[i];
 9             int left = i-1, right = i+1;
10             for(;left>=0 && height[i]<=height[left];--left)  area += height[i];
11             for(;right<height.size() && height[i]<=height[right];++right)  area += height[i];
12             ret = max(ret, area);
13         }
14         return ret;
15     }
16     int largestRectangleArea(vector<int>& height) {
17         //return largestRectangleArea2(height);
18         if(height.size()==0) return 0;
19         
20         height.push_back(-1);
21         stack<int> st;
22         int ret = numeric_limits<int>::min(), hId, width, area, start;
23         for(int i=0;i<height.size();++i) {
24             if(st.empty()) {
25                 st.push(i); 
26                 start = st.top();
27             }
28             if(height[st.top()] < height[i]) st.push(i);
29             while(!st.empty() && height[st.top()] > height[i]) {
30                     hId = st.top(); st.pop();
31                     width = st.empty()? i-start: i-st.top()-1;
32                     ret = max(ret, width * height[hId]);
33             }
34             st.push(i);
35         }
36         return ret;
37     }
38 };
 1 class Solution {
 2 public:
 3     void clear(vector<int> &vec) {
 4         for(int i=0;i<vec.size();++i) vec[i] = 0;
 5     }
 6     void clearStack(stack<int> &st) {
 7         while(!st.empty()) st.pop();
 8     }
 9     int largestRectangleArea(vector<int>& height) {
10         if(height.size()==0) return 0;
11         
12         height.push_back(-1);
13         stack<int> st;
14         int ret = numeric_limits<int>::min(), hId, width, area, start;
15         for(int i=0;i<height.size();++i) {
16             if(st.empty()) {
17                 st.push(i); 
18                 start = st.top();
19             }
20             if(height[st.top()] < height[i]) st.push(i);
21             while(!st.empty() && height[st.top()] > height[i]) {
22                     hId = st.top(); st.pop();
23                     width = st.empty()? i-start: i-st.top()-1;
24                     ret = max(ret, width * height[hId]);
25             }
26             st.push(i);
27         }
28         return ret;
29     }
30     int maximalRectangle(vector<vector<char>>& matrix) {
31         if(matrix.size() == 0) return 0;
32         
33         vector<int> height(matrix[0].size());
34         
35         int ret = numeric_limits<int>::min(), start;
36         for(int i=0;i<matrix.size();++i) {
37             for(int j=0;j<matrix[0].size();++j) {
38                 if(matrix[i][j]=='1') height[j]++;
39                 else height[j] = 0;
40             }
41             
42             ret = max(ret, largestRectangleArea(height));
43         }
44         
45         return ret;
46     }
47 };

 

posted @ 2015-11-06 14:32  流白  阅读(197)  评论(0编辑  收藏  举报