编写一个程序，求s=1+(1+2)+(1+2+3)+…+(1+2+3+…+n)的值

1 #import <Foundation/Foundation.h>

2
3 int main(int argc, const char * argv[]) {
4     @autoreleasepool {
5         int shu=0,he=0;
6         for (int i=1; i<=100; i++) {
7             shu+=i;
8             he+=shu;
9             //printf("he is:%d\n",he);
10         }
11         printf("he is:%d\n",he);
12         return 0;
13     }
14 }

执行结果：