Assume you have an array of length n initialized with all 0's and are given k update operations.
Each operation is represented as a triplet: [startIndex, endIndex, inc] which increments each element of subarray A[startIndex ... endIndex](startIndex and endIndex inclusive) with inc.
Return the modified array after all k operations were executed.
Example:
Given: length = 5, updates = [ [1, 3, 2], [2, 4, 3], [0, 2, -2] ] Output: [-2, 0, 3, 5, 3]
Explanation:
Initial state: [ 0, 0, 0, 0, 0 ] After applying operation [1, 3, 2]: [ 0, 2, 2, 2, 0 ] After applying operation [2, 4, 3]: [ 0, 2, 5, 5, 3 ] After applying operation [0, 2, -2]: [-2, 0, 3, 5, 3 ]
vector<int> getModifiedArray(int length, vector<vector<int>>& updates) { vector<int> ret(length, 0); for (int i = 0; i < updates.size(); i++) { ret[updates[i][0]] += updates[i][2]; int endIdx = updates[i][1] + 1; if (endIdx < length) ret[endIdx] -= updates[i][2]; } for (int i = 1; i < length; i++) { ret[i] += ret[i - 1]; } return ret; }
总想把每一篇文章精雕细琢之后以完美的面貌示人,就像演员在演出前都要彩排,总想准备好之后再去展现精彩的一面,但人生的每一刻都是精彩的,就算现在还不完善也要发出来,作为自己一直在学习的一种见证。