[Leetcode 24] 35 Valid Sudoku
Problem:
Determine if a Sudoku is valid, according to: Sudoku Puzzles - The Rules.
The Sudoku board could be partially filled, where empty cells are filled with the character '.'
.
A partially filled sudoku which is valid.
Analysis:
Simulation problem, the nice part here is use a same function for three different kinds of test as showed in code.
Code:
1 public class Solution { 2 public boolean isValidSudoku(char[][] board) { 3 // Start typing your Java solution below 4 // DO NOT write main() function 5 for (int i=0; i<9; ++i) {//judge row 6 if (!judge(board, i, 0, 1, 9)) 7 return false; 8 } 9 10 for (int j=0; j<9; ++j) {//judge column 11 if (!judge(board, 0, j, 9, 1)) 12 return false; 13 } 14 15 for (int i=0; i<3; ++i) {//judge block 16 for (int j=0; j<3; ++j) { 17 if (!judge(board, i*3, j*3, 3, 3)) 18 return false; 19 } 20 } 21 22 return true; 23 } 24 25 private boolean judge(char[][] board, int r, int c, int rl, int cl) { 26 int[] hashT = {0,0,0,0,0,0,0,0,0}; 27 28 for (int i=r; i<r+rl; ++i) { 29 for (int j=c; j<c+cl; ++j) { 30 if (board[i][j] != '.') { 31 int idx = board[i][j]-'0'-1; 32 33 if (hashT[idx] != 0) { 34 return false; 35 } else { 36 hashT[idx] ++; 37 } 38 } 39 } 40 } 41 42 return true; 43 } 44 }
Attention:
Sometimes it may have Time Limit Exceeded error....