hdu5347 MZL's chemistry(打表)
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MZL's chemistry
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 373 Accepted Submission(s): 310
Problem Description
MZL define F(X) as the first ionization energy of the chemical element X
Now he get two chemical elements U,V,given as their atomic number,he wants to compare F(U) and F(V)
It is guaranteed that atomic numbers belongs to the given set:{1,2,3,4,..18,35,36,53,54,85,86}
It is guaranteed the two atomic numbers is either in the same period or in the same group
It is guaranteed that x≠y
Now he get two chemical elements U,V,given as their atomic number,he wants to compare F(U) and F(V)
It is guaranteed that atomic numbers belongs to the given set:{1,2,3,4,..18,35,36,53,54,85,86}
It is guaranteed the two atomic numbers is either in the same period or in the same group
It is guaranteed that x≠y
Input
There are several test cases
For each test case,there are two numbers u,v,means the atomic numbers of the two element
For each test case,there are two numbers u,v,means the atomic numbers of the two element
Output
For each test case,if F(u)>F(v),print "FIRST BIGGER",else print"SECOND BIGGER"
Sample Input
1 2
5 3
Sample Output
SECOND BIGGER
FIRST BIGGER
百度第一电离能,然后打个表就好
1 /** 2 * code generated by JHelper 3 * More info: https://github.com/AlexeyDmitriev/JHelper 4 * @author xyiyy 5 */ 6 7 #include <iostream> 8 #include <fstream> 9 10 //##################### 11 //Author:fraud 12 //Blog: http://www.cnblogs.com/fraud/ 13 //##################### 14 //#pragma comment(linker, "/STACK:102400000,102400000") 15 #include <iostream> 16 #include <sstream> 17 #include <ios> 18 #include <iomanip> 19 #include <functional> 20 #include <algorithm> 21 #include <vector> 22 #include <string> 23 #include <list> 24 #include <queue> 25 #include <deque> 26 #include <stack> 27 #include <set> 28 #include <map> 29 #include <cstdio> 30 #include <cstdlib> 31 #include <cmath> 32 #include <cstring> 33 #include <climits> 34 #include <cctype> 35 36 using namespace std; 37 38 double f[100] = {1312.0, 2372.0, 520.2, 899.5, 800.6, 39 1086.5, 1402.3, 1313.9, 1681.0, 2080.7, 40 495.8, 737.7, 577.5, 786.5, 1011.8, 41 999.6, 1251.2, 1520.6, 418.8, 589.8, 42 633.1, 658.8, 650.9, 652.9, 717.3, 43 762.5, 760.4, 737.1, 745.5, 906.4, 44 578.8, 762, 947, 941, 1139.9, 45 1350.8, 403, 549.5, 600, 640.1, 46 652.1, 684.3, 702, 710.2, 719.7, 47 804.4, 731.0, 867.8, 558.3, 708.6, 48 834, 869.3, 1008.4, 1170.4, 375.7}; 49 50 double gao(int x) { 51 if (x == 85)return 890; 52 if (x == 86)return 1037; 53 return f[x - 1]; 54 } 55 56 class hdu5347 { 57 public: 58 void solve(std::istream &in, std::ostream &out) { 59 int a, b; 60 while (in >> a >> b) { 61 double x = gao(a); 62 double y = gao(b); 63 if (x > y) out << "FIRST BIGGER" << endl; 64 else out << "SECOND BIGGER" << endl; 65 } 66 } 67 }; 68 69 70 int main() { 71 std::ios::sync_with_stdio(false); 72 std::cin.tie(0); 73 hdu5347 solver; 74 std::istream &in(std::cin); 75 std::ostream &out(std::cout); 76 solver.solve(in, out); 77 return 0; 78 }