for循环语句之棋盘放粮食、百鸡百钱、纸张的折叠问题

1.棋盘放粮食

            int lszl = 1;

            for (int i = 1; i < 30; i++)
            {
                int x = 1;
                for (int j = 1; j <= i; j++)
                {
                    x = x * 2;
                }
                lszl = lszl + x;
            }
            double zl = lszl * 0.001;
            Console.WriteLine("放满整个棋盘所需要：" + zl + "kg的粮食");

2.百鸡百钱

 for (int i = 1; i < 50; i++)
            {
                for (int j = 1; j < 100; j++)
                {
                    for (int k = 1; k < 200; k++)
                    {
                        double a = i*2+j*1+k*0.5;
                        if (a == 100)
                        {
                            Console.WriteLine("买大鸡："+i+"只，小鸡"+j+"只，幼鸡"+k+"只");
                        }
                    }
                }
            }

3.一张纸厚度是0.1毫米，假设这张纸可以限次对折，问对折几次可以超过珠峰？8848米

 int a = 1;
                double z = 0.0001;

                for (int i = 1; i <= i+1; i++)
                {
                        z = z * 2;
                        if (z > 8848)
                        {  
                            a = i;
                            break;
                        }                    
                }
                Console.WriteLine("折" + a + "次可以跟珠穆朗玛峰一样高");