链接: https://oj.leetcode.com/problems/minimum-path-sum/


简单的动态规划.

[i][j]表示到达位置(i,j)时的最小sum


public class Solution
{

	public int minPathSum(int[][] grid)
	{
		int n=grid.length;
		int m=grid[0].length;
		for(int i=0;i<n;i++)			
			for(int j=0;j<m;j++)
			{
				if(i==0&&j>0)
					grid[i][j]+=grid[i][j-1];
				if(i>0&&j==0)
					grid[i][j]+=grid[i-1][j];
				if(i>0&&j>0)	
					grid[i][j]+=Math.min(grid[i-1][j],grid[i][j-1]);
			}
		return grid[n-1][m-1];

	}
}