摘要：
#includeint main(){ int n,m,p,left,right; int sum; int num[50010]; while(~scanf("%d%d%d%d%d",&n,&m,&p,&left,&right)){ sum=0; int kk=n/m; int th=1; ... 阅读全文
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摘要：
#includeint main(){ int n,m,p,left,right; int sum; int num[50010]; while(~scanf("%d%d%d%d%d",&n,&m,&p,&left,&right)){ sum=0; int kk=n/m; int th=1; ... 阅读全文
摘要：
H -LIGHTOJ 1127Time Limit:2000MSMemory Limit:32768KB64bit IO Format:%lld & %lluSubmitStatusDescriptionGivennintegers and a knapsack of weightW, you ha... 阅读全文
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