写个函数，把list1变成res，最好像Python的风格
list1=[["a1","a2"],["b1","b2"],["c1","c2"],["d1","d2"]]
res=[["a1", "a2"], ["a2", "b1"], ["b1", "b2"], ["b2", "c1"], ["c1", "c2"], ["c2", "d1"], ["d1", "d2"]]
代码如下：
>>> list1 = [["a1","a2"],["b1","b2"],["c1","c2"],["d1","d2"]] # 方法一：使用lambda表达式 >>> from functools import reduce >>> l = list(reduce(lambda x,y:x+y,list1)) >>> l ['a1', 'a2', 'b1', 'b2', 'c1', 'c2', 'd1', 'd2'] >>> res = [l[i:i+2] for i in range(len(l)-1)] >>> res [['a1', 'a2'], ['a2', 'b1'], ['b1', 'b2'], ['b2', 'c1'], ['c1', 'c2'], ['c2', 'd1'], ['d1', 'd2']] >>> l = [] >>> l [] # 方法二：使用sum()函数 >>> l = sum(list1, []) >>> l ['a1', 'a2', 'b1', 'b2', 'c1', 'c2', 'd1', 'd2'] >>> res = [l[i:i+2] for i in range(len(l)-1)] >>> res [['a1', 'a2'], ['a2', 'b1'], ['b1', 'b2'], ['b2', 'c1'], ['c1', 'c2'], ['c2', 'd1'], ['d1', 'd2']] >>>
