L1-018 大笨钟 python

python 实现：

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s=input() hour_str=str(s.split(":")[0]) # 在00到23之间 min_str=str(s.split(":")[1]) # 在00到59之间   hour=int(hour_str) min=int(min_str)   if hour<12 or (hour==12 and min==0):     print("Only {hour}:{min}.  Too early to Dang.".format(hour=hour_str,min=min_str)) else:     if min == 0:         for i in range(hour-12):             print("Dang",end="")         print()     else:         for i in range(hour-11):             print("Dang",end="")         print()