L1-022 奇偶分家 python

python 实现

num = int(input())
str = input()

odd=0
even=0

for i in range(num):
    temp=int(str.split(" ")[i])
    if temp%2==0:
        even+=1
    else:
        odd+=1

print("{odd} {even}".format(odd=odd,even=even))

 

posted @ 2024-06-28 15:26  豆豆是只乖狗狗  阅读(1)  评论(0编辑  收藏  举报