# -*- coding:cp936 -*-

def daysInYear():
    """
    题目:输入某年某月某日,判断这一天是这一年的第几天?
    程序分析:以3月5日为例,应该先把前两个月的加起来,然后再加上5天即本年的第几天,特殊情况,闰年且输入月份大于3时需考虑多加一天。
    """
    yearth = int(raw_input('年份:'))
    month = int(raw_input('月份:'))
    dayth = int(raw_input('日期:'))
    print "日期是:%d年%d月%d日" % (yearth, month, dayth)

    sum = 0
    days = {1:0,2:31,3:59,4:90,5:120,6:151,\
            7:181,8:212,9:243,10:273,11:304,12:334}
    sum += days[month]
    sum += dayth
    if month > 2:
        if yearth%400 == 0 or (yearth%4 == 0 and yearth%100 != 0):
            sum += 1
    print "这一天是这一年的第%d天" % sum 

if (__name__ == '__main__'):
    daysInYear()