HDU 2066 一个人的旅行

题解:最短路~

#include <cstdio>
#include <utility>
#include <cstring>
#include <queue>
using namespace std;
const int N=20005;
const int INF=9999999;
typedef pair<int,int>seg;
priority_queue<seg,vector<seg>,greater<seg> >q;
int d[N],u[N],v[N],w[N],head[N],next[N],a,b,c,m,n,k,p,cnt,min;
bool vis[N];
void build(){
    memset(head,-1,sizeof(head));
    for(int e=1;e<=m;e++){
        scanf("%d%d%d",&u[e],&v[e],&w[e]);
        n=n<u[e]?u[e]:n;
        n=n<v[e]?v[e]:n;
        u[e+m]=v[e]; v[e+m]=u[e]; w[e+m]=w[e];
        next[e]=head[u[e]]; head[u[e]]=e;
        next[e+m]=head[u[e+m]]; head[u[e+m]]=e+m;
    }
}
int Dijkstra(int src){
    memset(vis,0,sizeof(vis));
    for(int i=0;i<=n;i++)d[i]=INF;
    d[src]=0;
    q.push(make_pair(d[src],src));
    while(!q.empty()){
        seg now=q.top(); q.pop();
        int x=now.second;
        if (vis[x]) continue; vis[x]=1;
        for(int e=head[x];e!=-1;e=next[e])
        if(d[v[e]]>d[x]+w[e]){
            d[v[e]]=d[x]+w[e];
            q.push(make_pair(d[v[e]],v[e]));
        }
        
    }
}
int main(){
    while(~scanf("%d%d%d",&m,&k,&p)){
        build();
        for(int e=2*m+1;e<=2*m+k;e++){
            scanf("%d",&v[e]);
            w[e]=0; u[e]=2*m+k+1;
            next[e]=head[u[e]]; head[u[e]]=e;
        }
        Dijkstra(2*m+k+1);
        int min=INF;
        for(int i=0;i<p;i++){
            scanf("%d",&a);
            min=d[a]<min?d[a]:min;
        }      
        printf("%d\n",min);             
    }
    return 0;
}
posted @ 2014-03-19 13:55  forever97  阅读(170)  评论(0编辑  收藏  举报