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zoj 2105 Number Sequence

ZOJ Problem Set - 2105

Number Sequence

Time Limit: 1 Second      Memory Limit: 32768 KB

A number sequence is defined as follows:

f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7.

Given A, B, and n, you are to calculate the value of f(n).


Input

The input consists of multiple test cases. Each test case contains 3 integers A, B and n on a single line (1 <= A, B <= 1000, 1 <= n <= 100,000,000). Three zeros signal the end of input and this test case is not to be processed.


Output

For each test case, print the value of f(n) on a single line.


Sample Input

1 1 3
1 2 10
0 0 0


Sample Output

2
5


Author: CHEN, Shunbao


Source: Zhejiang Provincial Programming Contest 2004
Submit    Status

 

//1385524 2008-03-29 22:34:43 Accepted  2105 C++ 0 832 Wpl 
#include <iostream>
using namespace std;
int main()
{
    
int a,b,d;
    
long n;
    
int arry[49];
    arry[
1]=1;
    arry[
2]=1;
    cin
>>a>>b>>n;
    
while(a!=0&&b!=0&&n!=0)
    {
        
for(d=3;d<=48;d++)
            arry[d]
=(arry[d-1]*a%7+arry[d-2]*b%7)%7;
        cout
<<arry[(n-1)%48+1]<<endl;            
        cin
>>a>>b>>n;
    }
}

 

posted @ 2009-05-09 13:49  往往  阅读(514)  评论(0编辑  收藏  举报