获取文件夹下所有文件名

 

In [1]:
import os
from pathlib import Path
import glob

方法1

In [3]:
dirpath="D:\\test\\1"
#判断是否是目录
if os.path.isdir(dirpath):
    img_names=[]
    # 获取所有文件名
    dir_names = os.listdir(dirpath)
    for img_name in dir_names:
        # 获取固定后缀文件名
        if os.path.splitext(img_name)[1] == '.jpg':
            img_names.append(img_name)
else:
    print("路径错误,请输入目录!")
    
print("dir_names:",dir_names)
print("img_names:",img_names)
print("os.path.splitext(img_name):",os.path.splitext(img_names[0]))
dir_names: ['66734.jpg', '66734.txt', '66991.jpg', '66991.txt', '67046.jpg', '67046.txt', '68248.jpg', '68248.txt', '68351.jpg', '68351.txt', '68550.jpg', '68550.txt']
img_names: ['66734.jpg', '66991.jpg', '67046.jpg', '68248.jpg', '68351.jpg', '68550.jpg']
os.path.splitext(img_name): ('66734', '.jpg')

 

方法2

In [4]:
# 获取所有文件路径
file_paths=glob.glob(dirpath)
# 获取固定后缀文件路径
img_paths=glob.glob(dirpath+"\\*.jpg")
print("file_paths:",file_paths)
print("img_paths:",img_paths)
file_paths: ['D:\\test\\1']
img_paths: ['D:\\test\\1\\66734.jpg', 'D:\\test\\1\\66991.jpg', 'D:\\test\\1\\67046.jpg', 'D:\\test\\1\\68248.jpg', 'D:\\test\\1\\68351.jpg', 'D:\\test\\1\\68550.jpg']

 

方法3

In [5]:
# 获取固定后缀文件路径
image_suffixes = (".jpeg", ".jpg", ".png", ".bmp")
img_paths=[p for p in Path(dirpath).glob("**/*") if p.suffix.lower() in image_suffixes]
print("img_paths:",img_paths)
print("img_paths[0]:",img_paths[0])
img_paths: [WindowsPath('D:/test/1/66734.jpg'), WindowsPath('D:/test/1/66991.jpg'), WindowsPath('D:/test/1/67046.jpg'), WindowsPath('D:/test/1/68248.jpg'), WindowsPath('D:/test/1/68351.jpg'), WindowsPath('D:/test/1/68550.jpg')]
img_paths[0]: D:\test\1\66734.jpg
posted @ 2020-12-05 23:27  forest_128  阅读(405)  评论(0编辑  收藏  举报