leetcode-Minimum Depth of Binary Tree
1 class Solution { 2 public: 3 int minDepth(TreeNode *root) { 4 if (root == nullptr) return 0; 5 if (root->left != nullptr&&root->right != nullptr) 6 { 7 int lDepth = minDepth(root->left); 8 int rDepth = minDepth(root->right); 9 return (lDepth<rDepth?lDepth+1:rDepth+1); 10 } 11 if (root->left != nullptr) 12 { 13 return 1+minDepth(root->left); 14 } 15 if (root->right != nullptr) 16 { 17 return 1+minDepth(root->right); 18 } 19 return 1;//只有一个根节点时。 20 } 21 };