<?xml version="1.0"?> <aws:UrlInfoResponse xmlns:aws="http://alexa.amazonaws.com/doc/2005-10-05/"> <aws:Response xmlns:aws="http://awis.amazonaws.com/doc/2005-07-11"> <aws:UrlInfoResult> <aws:Alexa> <aws:ContactInfo> <aws:Email>baidu_dns_master@baidu.com</aws:Email> </aws:ContactInfo> <aws:Alexa> </aws:UrlInfoResult> </aws:Response> </aws:UrlInfoResponse> 假如你要取得<aws:Email>节点,诶,你发现<aws:UrlInfoResponse>和<aws:Response>节点的命名空间马甲是一样的。
这个时候怎么办呢?难道是添加两次aws命名空间?其实不然。做法如下:
1.我们只要添加<aws:Response>节点的命名空间。
xnm.AddNamespace("aws", "http://awis.amazonaws.com/doc/2005-07-11");
2.取得根节点,这样我们就可以忽略根结点的命名空间,然后应用XPath取得你想要的节点。
XmlElement xe = xd.DocumentElement;
XmlNodeList xnl = xe.SelectNodes(
"//aws:Response/aws:UrlInfoResult/aws:Alexa/aws:ContactInfo/aws:Email", xnm);
直接这样取好像也可以:
XmlNodeList xnl = xd.SelectNodes(
"//aws:Response/aws:UrlInfoResult/aws:Alexa/aws:ContactInfo/aws:Email", xnm);
这样我们就可以得到<aws:Email>节点了,然后打印出来
foreach (XmlNode xn1 in xnl) { Response.Write(xn1.InnerXml.ToString() + "</br>"); }
完整代码:
XmlDocument xd = new XmlDocument(); xd.Load(Server.MapPath(".")+"/a.xml"); XmlNamespaceManager xnm = new XmlNamespaceManager(xd.NameTable); xnm.AddNamespace("aws", "http://awis.amazonaws.com/doc/2005-07-11"); XmlElement xe = xd.DocumentElement; XmlNodeList xnl = xe.SelectNodes( "//aws:Response/aws:UrlInfoResult/aws:Alexa/aws:ContactInfo/aws:Email", xnm); //XmlNodeList xnl = xd.SelectNodes( //"//aws:Response/aws:UrlInfoResult/aws:Alexa/aws:ContactInfo/aws:Email", xnm); foreach (XmlNode xn1 in xnl) { Response.Write(xn1.InnerXml.ToString() + "</br>"); }
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譬如要讀到DataSet中,如:
XmlDocument doc = new XmlDocument();
doc.Load(filename);
XmlNamespaceManager xnm = new XmlNamespaceManager(doc.NameTable);
xnm.AddNamespace("s", "uuid:BDC6E3F0-6DA3-11d1-A2A3-00AA00C14882");
xnm.AddNamespace("rs", "urn:schemas-microsoft-com:rowset");XmlNode node = doc.SelectSingleNode("//xml/rs:data", xnm);
XmlNodeReader reader = new XmlNodeReader(node);
ds.ReadXml(reader);