二叉树基本操作
树model
package com.sly.uploadfile.algorithm; /** * Created by fmgao on 2019/7/24. */ public class TreeNode01<T> { T value; TreeNode01<T> leftChild; TreeNode01<T> rightChild; TreeNode01() { } TreeNode01(T value) { this.value = value; } /** * 增加左子节点 * * @param value */ public void addLeft(T value) { TreeNode01<T> leftChild = new TreeNode01<T>(); this.leftChild = leftChild; } /** * 增加右子节点 * * @param value */ public void addRight(T value) { TreeNode01<T> rightChild = new TreeNode01<>(); this.rightChild = rightChild; } @Override public boolean equals(Object obj) { if (!(obj instanceof TreeNode01)) { return false; } return this.value.equals(((TreeNode01<?>) obj).value); } @Override public int hashCode() { return this.value.hashCode(); } @Override public String toString() { return this.value == null ? "" : this.value.toString(); } }
树的基本操作
package com.sly.uploadfile.algorithm; import java.util.ArrayList; import java.util.LinkedList; import java.util.List; import java.util.Queue; /** * Created by fmgao on 2019/7/24. */ public class TreeNodeTools { /** * 判断树种节点个数 * * @param root * @param <T> * @return */ public static <T> int getTreeNum(TreeNode01<T> root) { if (root == null) { return 0; } return getTreeNum(root.leftChild) + getTreeNum(root.rightChild) + 1; } /** * 判断树的深度 * * @param root * @param <T> * @return */ public static <T> int getTreeDepth(TreeNode01<T> root) { if (root == null) { return 0; } int leftDepth = getTreeDepth(root.leftChild) + 1; int rightDepth = getTreeDepth(root.rightChild) + 1; return Math.max(leftDepth, rightDepth); } /** * 前序遍历 * * @param root * @param <T> */ public static <T> void preOrderTravel(TreeNode01<T> root) { if (root == null) { return; } visitNode(root); preOrderTravel(root.leftChild); preOrderTravel(root.rightChild); } /** * 中序遍历 * * @param root * @param <T> */ public static <T> void midOrderTravel(TreeNode01<T> root) { if (root == null) { return; } midOrderTravel(root.leftChild); visitNode(root); midOrderTravel(root.rightChild); } /** * 后续遍历 * * @param root * @param <T> */ public static <T> void backOrderTravel(TreeNode01<T> root) { if (root == null) { return; } backOrderTravel(root.leftChild); backOrderTravel(root.rightChild); visitNode(root); } /** * 访问node节点 * * @param node01 * @param <T> */ public static <T> void visitNode(TreeNode01<T> node01) { System.out.println(node01.value + "\t"); } /** * 分层遍历 * * @param root * @param <T> */ public static <T> void levelTravel(TreeNode01<T> root) { Queue<TreeNode01<T>> q = new LinkedList<TreeNode01<T>>(); q.offer(root); while (!q.isEmpty()) { TreeNode01<T> tmp = q.poll(); visitNode(tmp); if (tmp.leftChild != null) { q.offer(tmp.leftChild); } if (tmp.rightChild != null) { q.offer(tmp.rightChild); } } } /** * 求第K层节点个数 * * @param root * @param k * @param <T> * @return */ public static <T> int getNumForKLevel(TreeNode01<T> root, int k) { if (root == null || k < 1) { return 0; } if (k == 1) { return 1; } int leftNum = getNumForKLevel(root.leftChild, k - 1); int rightNum = getNumForKLevel(root.rightChild, k - 1); return leftNum + rightNum; } /** * 求二叉树种叶子节点的个数 * * @param root * @param <T> * @return */ public static <T> int getLeafNum(TreeNode01<T> root) { if (root == null) { return 0; } if (root.leftChild == null && root.rightChild == null) { return 1; } int leftNum = getLeafNum(root.leftChild); int rightNum = getLeafNum(root.rightChild); return leftNum + rightNum; } /** * 交换根节点的左右子树 * * @param root * @param <T> * @return */ public static <T> TreeNode01<T> exchange(TreeNode01<T> root) { if (root == null) { return null; } TreeNode01<T> left = exchange(root.leftChild); TreeNode01<T> right = exchange(root.rightChild); root.leftChild = right; root.rightChild = left; return root; } /** * 查看node是否是root的节点 * * @param root * @param node * @param <T> * @return */ public static <T> boolean nodeIsChild(TreeNode01<T> root, TreeNode01<T> node) { if (root == null || node == null) { return false; } if (root == node) { return true; } boolean isFind = nodeIsChild(root.leftChild, node); if (!isFind) { isFind = nodeIsChild(root.rightChild, node); } return isFind; } /** * 返回lNode 和 rNode 以root为根节点的公共父节点 * * @param root * @param lNode * @param rNode * @param <T> * @return */ public static <T> TreeNode01<T> findAllFatherNode(TreeNode01<T> root, TreeNode01<T> lNode, TreeNode01<T> rNode) { if (lNode == root || rNode == root) { return root; } if (root == null || lNode == null || rNode == null) { return null; } // 如果lNode是左子树的节点 if (nodeIsChild(root.leftChild, lNode)) { if (nodeIsChild(root.rightChild, rNode)) { return root; } else { return findAllFatherNode(root.leftChild, lNode, rNode); } } else { if (nodeIsChild(root.leftChild, rNode)) { return root; } else { return findAllFatherNode(root.rightChild, lNode, rNode); } } } /** * 根据前序和中序构建二叉树 * * @param pre * @param mid * @param <T> * @return */ public static <T> TreeNode01<T> getTreeFromPreAndMid(List<T> pre, List<T> mid) { if (pre == null || mid == null || pre.size() == 0 || mid.size() == 0) { return null; } if (pre.size() == 1) { return new TreeNode01<T>(pre.get(0)); } TreeNode01<T> root = new TreeNode01<T>(pre.get(0)); // 找出根节点在中序中的位置 int index = 0; while (!mid.get(index++).equals(pre.get(0))) { } // 构建左子树的前序 List<T> preLeft = new ArrayList<T>(index); // 中子树的前序 List<T> midLeft = new ArrayList<T>(index); for (int i = 1; i < index; i++) { preLeft.add(pre.get(i)); } for (int i = 0; i < index - 1; i++) { midLeft.add(mid.get(i)); } // 重建左子树 root.leftChild = getTreeFromPreAndMid(preLeft, midLeft); // 右子树的前序 List<T> preRight = new ArrayList<T>(pre.size() - index - 1); // 右子树的中序 List<T> midRight = new ArrayList<T>(pre.size() - index - 1); for (int i = 0; i <= pre.size() - index - 1; i++) { preRight.add(pre.get(index + i)); } for (int i = 0; i <= pre.size() - index - 1; i++) { midRight.add(mid.get(index + i)); } // 重建→子树 root.rightChild = getTreeFromPreAndMid(preRight, midRight); return root; } public static <T> boolean equals(TreeNode01<T> node1, TreeNode01<T> node2) { if (node1 == null && node2 == null) { return true; } else if (node1 == null || node2 == null) { return false; } boolean isEqual = node1.value.equals(node2.value); boolean isLeftEqual = equals(node1.leftChild, node2.leftChild); boolean isRightEqual = equals(node1.rightChild, node2.rightChild); return isEqual && isLeftEqual && isRightEqual; } }