scala(一)
1、变量和常量
scala> var a:String="hello"
a: String = hello
scala> var a="ji"
a: String = ji
scala> var a=1
a: Int = 1
scala> var a:Int=1--->可以定义变量的时候定义类型
a: Int = 1
scala> var a:Int=2
a: Int = 2
scala> var a="hello"
a: String = hello
scala> var a:String="world"
a: String = world
scala> var a:Integer=22---->integer兼容int类型
a: Integer = 22
scala> val a = 20;---->常量,不可更改
a: Int = 20
scala> a=100
<console>:12: error: reassignment to val
a=100
^
scala> var a = 10;---->变量可更改
a: Int = 10
scala> a = 200
a: Int = 200
scala> 1 to 10
res3: scala.collection.immutable.Range.Inclusive = Range 1 to 10
scala> var a = 1 to 10--->定义一个数组类型
a: scala.collection.immutable.Range.Inclusive = Range 1 to 10
--->类型转换
scala> 1.to
to toByte toDegrees toFloat toInt toOctalString toShort
toBinaryString toChar toDouble toHexString toLong toRadians toString
scala> 1.tostring
<console>:12: error: value tostring is not a member of Int
1.tostring
^
scala> 1.Tostring
<console>:12: error: value Tostring is not a member of Int
1.Tostring
^
scala> 1.toString
res6: String = 1
scala> 1.toDouble
res7: Double = 1.0
scala> 1.toByte
res8: Byte = 1
2、操作符重载
scala> 1+2
res9: Int = 3
scala> 1.+(2)--->通过.调用方法,括号里面相当于调用的加法方法的参数
res10: Int = 3
scala> 1.-(2)
res11: Int = -1
scala> 1.*(2)
res12: Int = 2
scala> 1.%(2)
res13: Int = 1
scala> 1.to(10)
res14: scala.collection.immutable.Range.Inclusive = Range 1 to 10
3、scala没有++,–,只有+=
scala> var a = 100;
a: Int = 100
scala> a+=1;
scala> a
res25: Int = 101
scala> a+=100;
scala> a
res27: Int = 201
4、导入包
scala> import scala.math._
import scala.math._ --->下划线表示通配符
scala> min(1,2)---->Scala函数没有对象,方法有对象,方法通过对象调用
res29: Int = 1
scala> 1.toString --->对于没有参数的方法可以省略括号
res30: String = 1
scala> 1 toString --->运算符的方式
<console>:15: warning: postfix operator toString should be enabled
by making the implicit value scala.language.postfixOps visible.
This can be achieved by adding the import clause 'import scala.language.postfixOps'
or by setting the compiler option -language:postfixOps.
See the Scaladoc for value scala.language.postfixOps for a discussion
why the feature should be explicitly enabled.
1 toString
^
res31: String = 1
scala> 1.toString() --->方法的形式
res32: String = 1
5、apply方法
scala> "hello"(0) --->隐含调用apply方法
res35: Char = h
scala> "hello".apply(0)---->等价于上面那个
res36: Char = h
scala> "hello".apply(1)
res37: Char = e
scala> val a = "hello"
a: String = hello
scala> a(0)
res38: Char = h
6、条件表达式
scala> var x = 3;
x: Int = 3
scala> var s = 0;
s: Int = 0
scala> if (x>1) s=1 else s = -1;
--->等价于上面的表达式
scala> s
res43: Int = 1
scala> var b = if(x>1) 1 else -1; ---->scala的条件表达式都是有值的
b: Int = 1
scala> val c = if(x>1) 1 else "hello"
c: Any = 1 ---->any类型是int类型和string类型的父类
scala>
6、类型转换
scala> "1000". toInt
res45: Int = 1000
7、unit类(赋值语句没有值,用unit类表示)
scala> val y = (s=1);
y: Unit = ()
scala> val y:Unit=(); ---->可以声明为unit类型,相当于void
y: Unit = ()
8、Scala没有switch语句
scala> if(x>0) 1 --->如何没有定义类型,会自动分配一个anyval类型
res46: AnyVal = 1
9、进入粘贴模式(ctr+d结束粘贴模式)
scala> :paste
// Entering paste mode (ctrl-D to finish)
if(x>1){1}
else -1
// Exiting paste mode, now interpreting.
res48: Int = 1
scala>
10、Java—->.java–javac—->.class——>程序
打印输出
scala> print(1)
1
scala> println(2)
2
scala> printf("name is %s, age=%d","tong",12)
name is tong, age=12
scala>
从终端读取
scala> val name = readLine("请输入密码:");
<console>:14: warning: method readLine in trait DeprecatedPredef is deprecated (since 2.11.0): use the method in `scala.io.StdIn`
val name = readLine("请输入密码:");
^
请输入密码:name: String = 12323
scala>
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