摘要: function to_last_month($num){ $today = date("Y-m-d"); $arr = array(); $m = '-'.$num.' month'; $old_time = strtotime($m,strtotime($today)); for($i = 0;$i <= $num-1; ++$i){ $t = strtotime("+$i... 阅读全文
posted @ 2019-03-12 16:52 风79 阅读(1143) 评论(0) 推荐(0) 编辑