UVA 10783 Odd Sum

Given a range [a, b], you are to find the summation of all the odd integers in this range. For example, the summation of all the odd integers in the range [3, 9] is 3 + 5 + 7 + 9 = 24.

Input 

There can be at multiple test cases. The first line of input gives you the number of test cases, T ( 1T100). Then T test cases follow. Each test case consists of 2 integers a and b ( 0ab100) in two separate lines.

Output 

For each test case you are to print one line of output - the serial number of the test case followed by the summation of the odd integers in the range [a, b].

Sample Input 

2
1
5
3
5

Sample Output 

Case 1: 9
Case 2: 8

题意：给定两个整数，求这两个数之间所有奇数的和。
思路：判断出两个正整数的奇偶性，然后累加，注意求和的参数的初始化！
AC源代码（C语言）：

#include<stdio.h>
int main()
{
  int a,b,T,i,j,sum;
  while(scanf("%d",&T)==1)
   {
     for(i=1;i<=T;i++)
      {
        sum=0;
        scanf("%d%d",&a,&b);
        for(j=a;j<=b;j++)
         {
           if(j%2==1)  sum+=j;             
         } 
        printf("Case %d:%d\n",i,sum);                
      } 
     break;  //保证只输入T组数据！！！！！                                            
   }    
  return 0;  
}

2013-03-14