python 获取本周 ,上周,本月,上月,本季,上季,今年, 去年的第一天和最后一天

import datetime
from datetime import timedelta
 
now = datetime.datetime.now()


# 获取当前月的天数
month = 2
days = (datetime.date(2022, month + 1, 1) - datetime.timedelta(days=1)).day
 
#今天
today = now
 
#昨天
yesterday = now - timedelta(days=1)
 
#明天
tomorrow = now + timedelta(days=1)<br><br>#当前季度

#本周第一天和最后一天
this_week_start = now - timedelta(days=now.weekday())
this_week_end = now + timedelta(days=6-now.weekday())
 
#上周第一天和最后一天
last_week_start = now - timedelta(days=now.weekday()+7)
last_week_end = now - timedelta(days=now.weekday()+1)
 
#本月第一天和最后一天
this_month_start = datetime.datetime(year, month, 1)
if month == 12:
this_month_end = datetime.datetime(year + 1, 1, 1) - timedelta(days=1)
else:
this_month_end = datetime.datetime(year, month + 1, 1) - timedelta(days=1)
#上月第一天和最后一天 
last_month_end = this_month_start - timedelta(days=1)
last_month_start = datetime.datetime(last_month_end.year, last_month_end.month, 1)

#本季第一天和最后一天 month = (now.month - 1) - (now.month - 1) % 3 + 1
this_quarter_start = datetime.datetime(now.year, month, 1)
this_quarter_end = datetime.datetime(now.year, month + 3, 1) - timedelta(days=1)

#上季第一天和最后一天
last_quarter_end = this_quarter_start - timedelta(days=1)
last_quarter_start = datetime.datetime(last_quarter_end.year, last_quarter_end.month - 2, 1)

#本年第一天和最后一天
this_year_start = datetime.datetime(now.year, 1, 1)
this_year_end = datetime.datetime(now.year + 1, 1, 1) - timedelta(days=1)

#去年第一天和最后一天 last_year_end = this_year_start - timedelta(days=1)
last_year_start = datetime.datetime(last_year_end.year, 1, 1)

  

posted @ 2021-12-17 11:37  长情不羁的五年  阅读(201)  评论(0编辑  收藏  举报