Ternary Calculation

Description

Complete the ternary calculation.

Input

There are multiple test cases. The first line of input contains an integer T indicating the number of test cases. For each test case:

There is a string in the form of "number₁operator_anumber₂operator_bnumber₃". Each operator will be one of {'+', '-' , '*', '/', '%'}, and each number will be an integer in [1, 1000].

Output

For each test case, output the answer.

Sample Input

5
1 + 2 * 3
1 - 8 / 3
1 + 2 - 3
7 * 8 / 5
5 - 8 % 3

Sample Output

7
-1
0
11
3

Note

The calculation "A % B" means taking the remainder of A divided by B, and "A / B" means taking the quotient. 

 

#include<iostream>
#include<cstdio>
#include<cstring>
#include<algorithm>
using namespace std;

char alp[] = { '+', '-' , '*', '/', '%' };

int judge(int a, char x, int b) {

    switch (x) {
    case '+':
        return a + b;
        break;
    case '-':
        return a - b;
        break;
    case '*':
        return a * b;
        break;
    case '/':
        return a / b;
        break;
    case '%':
        return a % b;
        break;
    }
}

int main(){
    int t, a, b, c;
    char al1, al2;
    cin >> t;
    while (t--) {
        int result = 0;
        scanf("%d %c %d %c %d", &a, &al1, &b, &al2, &c);
        if (al1 == alp[2] || al1 == alp[3]  || al1 == alp[4]) {
            result = judge(a, al1, b);
            result = judge(result, al2, c);
        }
　　　　　//之前没有考虑到这种情况，然后wa了
        else if ((al1 == alp[0] || al1 == alp[1]) && (al2 == alp[0] || al2 == alp[1])) {
            result = judge(a, al1, b);
            result = judge(result, al2, c);
        }
        else {
            result = judge(b, al2, c);
            result = judge(a, al1, result);
        }
        cout << result << endl;
    }
    return 0;
}