实验1 C语言输入输出和简单程序编写
1. 实验任务1
task1_1.c
#include<stdio.h> int main() { printf(" o \n"); printf("<H>\n"); printf("I I\n"); printf(" o \n"); printf("<H>\n"); printf("I I\n");
return 0; }
task1_2.c
#include<stdio.h> int main() { printf(" o o\n"); printf("<H> <H>\n"); printf("I I I I\n"); return 0; }
2. 实验任务2
task2.c
#include<stdio.h> int main() { double a, b, c; scanf("%lf%lf%lf", &a, &b, &c); if(a + b > c && a + c > b && b + c > a) printf("能构成三角形\n"); else printf("不能构成三角形\n"); return 0; }
3. 实验任务3
task3.c
#include<stdio.h> int main() { char ans1, ans2; printf("每次课前认真预习、课后及时复习了没? (输入y或Y表示有,输入n或N表示没有) : "); ans1 = getchar(); getchar(); printf("\n动手敲代码实践了没? (输入y或Y表示敲了,输入n或N表示木有敲) : "); ans2 = getchar(); if ((ans1 == 'y'||ans1 == 'Y') && (ans2 == 'y'||ans2 == 'Y')) printf("\n罗马不是一天建成的, 继续保持哦:)\n"); else printf("\n罗马不是一天毁灭的, 我们来建设吧\n"); return 0; }
问题回答:删除line9后,输入第一个“Y”或“N”后按回车,会跳过第二个问题,因为回车也是符号,会被判定为第二个问题的答案
4. 实验任务4
task4.c
#include<stdio.h> int main() { double x, y; char c1, c2, c3; int a1, a2, a3; scanf("%d%d%d", &a1, &a2, &a3); printf("a1 = %d, a2 = %d, a3 = %d\n", a1,a2,a3); scanf("%c%c%c", &c1, &c2, &c3); printf("c1 = %c, c2 = %c, c3 = %c\n", c1, c2, c3); scanf("%lf%lf", &x, &y); printf("x = %f, y = %lf\n",x, y); return 0; }
5. 实验任务5
task5.c
#include<stdio.h> int main() { int year; year=round(pow(10,9)/(3.15*pow(10,7))); printf("10亿秒约等于%d年\n", year); return 0; }
6. 实验任务6
task6_2.c
#include<stdio.h> #include<math.h> int main() { double x, ans; while(scanf("%lf", &x) != EOF) { ans = pow(x, 365); printf("%.2f的365次方: %.2f\n", x, ans); printf("\n"); } return 0; }
7. 实验任务7
task7.c
#include<stdio.h> #include<math.h> int main() { double C, F; while(scanf("%lf", &C) != EOF) { F = 9*C/5 + 32; printf("摄氏度c = %.2f时,华氏度f = %.2f\n", C, F); printf("\n"); } return 0; }
8. 实验任务8
task8.c
#include<stdio.h> #include<math.h> int main() { int a, b, c; double s, area; while(scanf("%d%d%d", &a, &b, &c) != EOF) { s = (a + b + c)/2.0; area = sqrt(s*(s - a)*(s - b)*(s - c)); printf("a = %d, b = %d, c = %d, area = %.3f\n", a, b, c, area); printf("\n"); } return 0; }