tsql比较两个时间之间的工作时间

我在这个网址http://beyondrelational.com/blogs/tc/archive/2009/02/27/tsql-challenge-2.aspx发现了这个tsql 的challenge。要求计算两个给点时间之间的工作时间，假定工作日的时间是从早上8点到到下午5点。

很显然，周末的时间不能计算在工作时间内。

题目给定了假设数据时：

ID          StartDate               EndDate
----------- ----------------------- -----------------------
1           2009-03-02 08:00:00.000 2009-03-02 15:00:00.000
2           2009-03-01 16:00:00.000 2009-03-03 14:00:00.000
3           2009-02-26 07:00:00.000 2009-02-26 22:00:00.000
4           2009-01-27 09:15:00.000 2009-01-27 17:15:00.000
5           2009-01-17 13:45:00.000 2009-01-19 07:45:00.000
6           2009-01-27 21:15:00.000 2009-01-28 09:15:00.000

应该得到的结果是：

StartDate               EndDate                 Hours       Minutes 
----------------------- ----------------------- ----------- ----------- 
2009-03-02 08:00:00.000 2009-03-02 15:00:00.000 7           0 
2009-03-01 16:00:00.000 2009-03-03 14:00:00.000 15          0 
2009-02-26 07:00:00.000 2009-02-26 22:00:00.000 9           0 
2009-01-27 09:15:00.000 2009-01-27 17:15:00.000 7           45 
2009-01-17 13:45:00.000 2009-01-19 07:45:00.000 0           0 
2009-01-27 21:15:00.000 2009-01-28 09:15:00.000 1           15

下面是我的解决方案：

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set datefirst 1; with cte1(id, startDate, endDate) as(     select 1, cast('2009-03-02 08:00:00.000' as datetime), cast('2009-03-02 15:00:00.000' as datetime) union all     select 2, CAST('2009-03-01 16:00:00.000' as datetime), CAST('2009-03-03 14:00:00.000' as datetime) union all     select 3, CAST('2009-02-26 07:00:00.000' as datetime), CAST('2009-02-26 22:00:00.000' as datetime) union all     select 4, CAST('2009-01-27 09:15:00.000' as datetime), CAST('2009-01-27 17:15:00.000' as datetime) union all     select 5, CAST('2009-01-17 13:45:00.000' as datetime), CAST('2009-01-19 07:45:00.000' as datetime) union all     select 6, CAST('2009-01-27 21:15:00.000' as datetime), CAST('2009-01-28 09:15:00.000' as datetime) )   --soluton 3 select id, startDate, endDate, SUM(case when minutes> 0 then minutes else 0 end) / 60 as hours,     SUM(case when minutes> 0 then minutes else 0 end)  % 60 as minutes from (     select *, isWeekday * DATEDIFF(minute, propStartDate, propEndDate) as minutes     from (         select *,             case DATEPART(weekday,  inStartDate)                 when 6 then 0                 when 7 then 0                 else 1 end as isWeekday,             case                 when N=1 and startDate < inStartDate then inStartDate                 when N=1 and startDate > inStartDate then startDate                 else inStartDate end as propStartDate,             case                 when DATEDIFF(day, inEndDate, endDate) = 0 and endDate < inEndDate then endDate                 when DATEDIFF(day, startDate, endDate) = 0 and endDate >= inEndDate then inEndDate                 else inEndDate end as propEndDate         from (             select *, dateadd(day, N-1, DATEADD(hour,8, DATEADD(day,DATEDIFF(day, 0, startDate), 0))) as inStartDate,                 dateadd(day, N-1, DATEADD(hour, 17, DATEADD(day,DATEDIFF(day, 0, startDate), 0))) as inEndDate                from cte1 c1 cross apply(                 select *                 from dbo.Number                 where N <= DATEDIFF(day, c1.startDate, c1.endDate) + 1) as c         ) as d     ) as d2 ) as d3   group by id, startDate, endDate

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1

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1

结果如下：

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1	<img style="border: 0; margin: 1px auto; display: block; float: none" title="result" border="0" alt="result" src="https://images.cnblogs.com/cnblogs_com/fgynew/WindowsLiveWriter/tsql_1491B/result_3.png" width="418" height="136">