Python实现计算器功能

有使用任何模块,仅仅使用基础语句,实现计算器部分功能,有界面,可以实现基础运算、连续多次运算、以及不使用“=”的连续运算(可以显示每步计算的结果),例如5+5+5+5+5,5+3*2-4等。但是,除法在连续运算时,没法运算小数位,因为设置的是int,会直接取整。具体代码如下:

 

#! /usr/bin/env python
#coding=utf-8
'''
除法在连续运算时,没法运算小数位,因为设置的是int,会直接取整
'''
from Tkinter import *
 
root = Tk(className = "计算器")
root.geometry("500x580")
 
class App:
 
    def __init__(self, master):
 
        frame1 = Frame(master,borderwidth = 10)
        frame1.pack()
 
        frame2 = Frame(master,borderwidth = 10)
        frame2.pack()
 
        frame3 = Frame(master,borderwidth = 10)
        frame3.pack()
 
        Button(frame2, text = "1",font = ("Courier 20 bold roman"),command=lambda: self.callback(1) ).grid(row=0,column=0)
        Button(frame2, text = "2",font = ("Courier 20 bold roman"),command=lambda: self.callback(2) ).grid(row=0,column=1)
        Button(frame2, text = "3",font = ("Courier 20 bold roman"),command=lambda: self.callback(3) ).grid(row=0,column=2)
        Button(frame2, text = "4",font = ("Courier 20 bold roman"),command=lambda: self.callback(4) ).grid(row=1,column=0)
        Button(frame2, text = "5",font = ("Courier 20 bold roman"),command=lambda: self.callback(5) ).grid(row=1,column=1)
        Button(frame2, text = "6",font = ("Courier 20 bold roman"),command=lambda: self.callback(6) ).grid(row=1,column=2)
        Button(frame2, text = "7",font = ("Courier 20 bold roman"),command=lambda: self.callback(7) ).grid(row=2,column=0)
        Button(frame2, text = "8",font = ("Courier 20 bold roman"),command=lambda: self.callback(8) ).grid(row=2,column=1)
        Button(frame2, text = "9",font = ("Courier 20 bold roman"),command=lambda: self.callback(9) ).grid(row=2,column=2)
        Button(frame2, text = "0",font = ("Courier 20 bold roman"),command=lambda: self.callback(0) ).grid(row=3,column=0)
        Button(frame2, text = "+",font = ("Courier 20 bold roman"),command=lambda: self.callback1("+") ).grid(row=3,column=1)
        Button(frame2, text = "-",font = ("Courier 20 bold roman"),command=lambda: self.callback1("-") ).grid(row=3,column=2)
        Button(frame2, text ="*",font = ("Courier 20 bold roman"),command=lambda: self.callback1("*") ).grid(row=4,column=1)
        Button(frame2, text ="/",font = ("Courier 20 bold roman"),command=lambda: self.callback1("/") ).grid(row=4,column=2)
        Button(frame2, text="=",font = ("Courier 20 bold roman"),command=self.result).grid(row=4,column=0)
        Button(frame3, text="clear",font = ("Courier 20 bold roman"),command=lambda: self.clear() ).grid()
 
        label_1 = Label(frame1,text="输入数字")
        label_1.pack()
 
        self.a = IntVar()
        self.a.set(0)
        e1 = Entry(frame1,font = ("Courier 20 bold roman"),textvariable = self.a)
        e1.pack(padx=20,pady = 5)
 
        #label_2 = Label(frame1,text="第二次输入数字")
        #label_2.pack()
 
        #self.b = IntVar()
        #self.b.set(0)
        #e2 = Entry(frame1,font = ("Courier 20 bold roman"),textvariable=self.b)
        #e2.pack(padx=20,pady = 5)
 
        label_3 = Label(frame1,text="运算符号")
        label_3.pack()
 
        self.c = IntVar()
        self.c.set("")
        e3 = Entry(frame1,font = ("Courier 20 bold roman"), textvariable = self.c)
        e3.pack(padx=20,pady = 5)
 
        label_4 = Label(frame1,text="运算结果")
        label_4.pack()
 
        self.d = IntVar()
        self.d.set(0)
        e4 = Entry(frame1,font = ("Courier 20 bold roman"), textvariable = self.d)
        e4.pack(padx=20,pady = 5)
 
        #算式的左数
        self.left = 0
        #算式的右数
        self.right = 0
        #在标签中显示值的
        self.i = 0
        #实现多位数的
        self.j = 0
        #连续多次运算时,保存左数的
        self.k = 0
        #连续多次运算
        #self.l = 0
        #运算符
        self.accept_sign = ""
 
    def callback1(self,t):
 
        if t == "+":
            self.c.set(t)
            self.result()
            self.accept_sign = "+"
 
        elif t == "-":
            self.c.set(t)
            self.result()
            self.accept_sign = "-"
 
        elif t == "*":
            self.c.set(t)
            self.result()
            self.accept_sign = "*"
 
        else:
            self.c.set(t)
            self.result()
            self.accept_sign = "/"
 
        if self.k == 0:
            self.left = self.a.get()
        else:
            self.left = self.k
        self.j = 0
        #self.l += 1
 
    def callback(self,t):
 
        if self.j == 0:
            self.i = t
            self.a.set(self.i)
        if self.j == 1:
            self.i = self.i * 10 + t
            self.a.set(self.i)
        if self.j == 2:
            self.i = self.i * 10 + t
            self.a.set(self.i)
        if self.j == 3:
            self.i = self.i * 10 + t
            self.a.set(self.i)
        if self.j == 4:
            self.i = self.i * 10 + t
            self.a.set(self.i)
        if self.j == 5:
            self.i = self.i * 10 + t
            self.a.set(self.i)
        if self.j == 6:
            self.i = self.i * 10 + t
            self.a.set(self.i)
        if self.j == 7:
            self.i = self.i * 10 + t
            self.a.set(self.i)
        if self.j == 8:
            self.i = self.i * 10 + t
            self.a.set(self.i)
        self.j += 1
 
    def result(self):
 
        self.right = self.a.get()
        if self.accept_sign == "+":
            self.d.set(self.left + self.right)
        if self.accept_sign == "-":
            self.d.set(self.left - self.right)
        if self.accept_sign == "*":
            self.d.set(self.left * self.right)
        if self.accept_sign == "/":
            self.d.set(float(self.left) / self.right)
        else:
            pass
        self.k = self.d.get()
        self.j = 0
        #self.l = 0
 
    def clear(self):
 
        self.accept_sign = ""
        self.a.set(0)
        self.c.set("")
        self.d.set(0)
        self.j = 0
        self.k = 0
self.left = 0
        self.right = 0
        #self.l = 0
 
 
App(root)
root.mainloop()  转载请注明蓝盾在线下载http://www.huan-mei.com
posted @ 2013-07-18 11:39  bytjj  阅读(476)  评论(0编辑  收藏  举报