Java常用

package kemuyi;

import com.sun.jmx.remote.internal.ArrayQueue;
import org.junit.Test;
import org.junit.experimental.theories.suppliers.TestedOn;

import java.util.*;
import java.util.function.BiFunction;
import java.util.function.Supplier;
import java.util.stream.Collectors;

public class KS20220107_1 {

@Test
public void testStack() {
    // Stack
    Deque<Integer> stack = new LinkedList<>(); // ArrayDeque
    stack.push(1);
    stack.push(2);
    stack.peek();
    stack.pop();
    stack.isEmpty();
}

@Test
public void testQueue() {
    // Queue
    Queue<Integer> queue = new LinkedList<>(); // ArrayDeque
    queue.offer(1);
    queue.add(2);

    queue.poll();
    queue.remove();
    queue.isEmpty();

    //Deque
    Deque<Integer> deque = new LinkedList<>(); // ArrayDeque
    deque.offerFirst(1);
    deque.offerFirst(2);
    System.out.println("Deque:" + deque.poll()); // 2
}

@Test
public void testList() {
    List<Student> students = Arrays.asList(
            new Student(1, 24, 180),
            new Student(2, 21, 170),
            new Student(3, 24, 165));
    Collections.sort(students, (o1, o2) -> {
        if (o1.age == o2.age) {
            return o1.height - o2.height;
        }
        return o1.age - o2.age;
    });
    System.out.println(students);
}

@Test
public void testSet() {
    Set<Student> hashSet = new HashSet<>();
    hashSet.add(new Student(1, 24, 180));
    hashSet.add(new Student(2, 21, 170));
    hashSet.add(new Student(3, 24, 165));
    // 对HashSet排序的话,必须返回LinkedHashSet
    Set<Student> collect = hashSet.stream().sorted((o1, o2) -> {
        if (o1.age == o2.age) {
            return o1.height - o2.height;
        }
        return o1.age - o2.age;
    }).collect(Collectors.toCollection(LinkedHashSet::new));
    System.out.println("HashSet排序:" + collect);

    // LinkedHashSet容器中元素的顺序和插入顺序保持一致
    Set<Student> linkedHashSet = new LinkedHashSet<>();
    linkedHashSet.add(new Student(1, 24, 180));
    linkedHashSet.add(new Student(2, 21, 170));
    linkedHashSet.add(new Student(3, 24, 165));

    linkedHashSet = linkedHashSet.stream().sorted((o1, o2) -> {
        if (o1.age == o2.age) {
            return o1.height - o2.height;
        }
        return o1.age - o2.age;
    }).collect(Collectors.toCollection(LinkedHashSet::new));
    System.out.println("LinkedHashSet排序:" + linkedHashSet);

    // TreeSet可以在构造的时候传入比较器,也可以和上面方式一样stream遍历sorted()
    Set<Student> treeSet = new TreeSet<>((o1, o2) -> {
        if (o1.age == o2.age) {
            return o1.height - o2.height;
        }
        return o1.age - o2.age;
    });
    treeSet.add(new Student(1, 24, 180));
    treeSet.add(new Student(2, 21, 170));
    treeSet.add(new Student(3, 24, 165));
    System.out.println("TreeSet排序:" + treeSet);

    treeSet.removeIf(student -> student.equals(new Student(1, 24, 180)));
    System.out.println("TreeSet遍历删除:" + treeSet);
}

@Test
public void testMap() {
    Map<String, Integer> strMap = new HashMap<>();
    strMap.put("A", 3);
    strMap.put("B", 5);
    strMap.put("C", 1);
    strMap.put("E", 9);
    strMap.put("D", 1);
    System.out.println("HashMap key默认升序排列:" + strMap);

    strMap = strMap.entrySet().stream()
            .sorted(Collections.reverseOrder(Map.Entry.comparingByValue()))
            .collect(Collectors.toMap(entry -> entry.getKey(), entry -> entry.getValue(), (k1, k2) -> k2, LinkedHashMap::new));
    System.out.println("HashMap 按Value降序排列:" + strMap);

    strMap = strMap.entrySet().stream()
            .sorted(Map.Entry.comparingByValue())
            .collect(Collectors.toMap(Map.Entry::getKey, Map.Entry::getValue, (k1, k2) -> k2, LinkedHashMap::new));
    System.out.println("HashMap 按Value升序排列:" + strMap);
    System.out.println();
    Map<Integer, Student> map = new HashMap<>();
    map.put(1, new Student(1, 24, 180));
    map.put(3, new Student(3, 24, 165));
    map.put(2, new Student(2, 21, 170));
    System.out.println("原始HashMap数据:" + map);

    map = map.entrySet().stream()
            .sorted(Map.Entry.comparingByValue((o1, o2) -> {
                if (o1.age == o2.age) {
                    return o1.height - o2.height;
                }
                return o1.age - o2.age;
            }))
            .collect(Collectors.toMap(Map.Entry::getKey, Map.Entry::getValue, (x, y) -> x, LinkedHashMap::new));
    System.out.println("HashMap 按value排序:" + map);

    // key:student  value:count
    Map<Student, Integer> map2 = new HashMap<>();
    map2.put(new Student(1, 24, 180), 12);
    map2.put(new Student(3, 24, 165), 8);
    map2.put(new Student(2, 21, 170), 9);
    map2 = map2.entrySet().stream()
            .sorted(Map.Entry.comparingByKey((o1, o2) -> {
                if (o1.age == o2.age) {
                    return o1.height - o2.height;
                }
                return o1.age - o2.age;
            }))
            .collect(Collectors.toMap(Map.Entry::getKey, Map.Entry::getValue, (x, y) -> x, LinkedHashMap::new));
    System.out.println("HashMap 按key排序:" + map2);

    map2.entrySet().removeIf(entry -> entry.getKey().equals(new Student(3, 24, 165)));
    System.out.println("HashMap 遍历删除:" + map2);
}

@Test
public void testTreeMap() {
    TreeMap<Integer, List<Student>> treeMap = new TreeMap<>();
    treeMap.computeIfAbsent(4, k -> new LinkedList<>()).add(new Student(1, 24, 180));
    treeMap.computeIfAbsent(8, k -> new LinkedList<>()).add(new Student(3, 24, 165));
    treeMap.computeIfAbsent(12, k -> new LinkedList<>()).add(new Student(2, 21, 170));

    System.out.println(treeMap.ceilingKey(5));
    System.out.println(treeMap.floorKey(5));
    System.out.println(treeMap.firstKey());

    treeMap.ceilingEntry(5);
    treeMap.floorEntry(5);

    treeMap.computeIfPresent(8, (key, students) -> {
        students.add(new Student(1, 1, 1));
        return students;
    });

    // 常用法
    if (treeMap.containsKey(8)) {
        treeMap.get(8).add(new Student(1, 1, 1));
    } else {
        treeMap.computeIfAbsent(8, k -> new LinkedList<>()).add(new Student(3, 3, 3));
    }

    // 遍历
    treeMap.forEach((k, v) -> System.out.println(k + ":" + v));

    Collection<List<Student>> values = treeMap.values();
}

@Test
public void testPQ() {
    Map<Integer, Student> map = new HashMap<>();
    map.put(1, new Student(1, 24, 180));
    map.put(3, new Student(3, 24, 165));
    map.put(2, new Student(2, 21, 170));

    PriorityQueue<Student> priorityQueue = new PriorityQueue<>((o1, o2) -> {
        if (o1.age == o2.age) {
            return o1.height - o2.height;
        }
        return o1.age - o2.age;
    });
    priorityQueue.addAll(map.values());

}

public static void main(String[] args) {
}

}

class Student {
public int id;
public int age;
public int height;

public Student(int id, int age, int height) {
    this.id = id;
    this.age = age;
    this.height = height;
}

@Override
public boolean equals(Object o) {
    if (this == o) return true;
    if (o == null || getClass() != o.getClass()) return false;
    Student student = (Student) o;
    return id == student.id && age == student.age && height == student.height;
}

@Override
public int hashCode() {
    return Objects.hash(id, age, height);
}

@Override
public String toString() {
    return "Student{" +
            "id=" + id +
            ", age=" + age +
            ", height=" + height +
            '}';
}

}

posted @ 2022-03-05 00:25  __Helios  阅读(35)  评论(0编辑  收藏  举报