数据转换-16进制字符

0. 在openEuler(推荐)或Ubuntu或Windows(不推荐)中完成下面任务

1. 在utils.h和utils.c中完成16进制字符'0'-'9','A'-'F','a'-'f'与十六进制数据0-15的转换功能（10’）：

int Hex2Char(unsigned int fromi,unsigned char * toc);
int Char2Hex(unsigned char fromc,unsigned int * toi);

2. 并写出测试代码测试上述函数(不能与下面代码一样)，比如：（10’）

unsigned char * c;
Hex2Char(1, &c)
//结果：c = '1'
Hex2Char(15, &c)
//结果：c = 'F'
unsigned int i;
Char2Hex('1', &i);
//结果：i = 1
Char2Hex('F', &i);
//结果：i = 15

3. 提交代码（或代码链接）和运行结果

代码：

//utils.c
#include<stdio.h>
#include"utils.h"
#include<string.h>
int Hex2Char(int fromi,char *toc)
{
    if(fromi>=0&&fromi<=9)
    {
     *toc= fromi+'0';
    } 
    else if(fromi>=10&&fromi<=15)
    {
     *toc = fromi+'A'-10;
    }
    else
    {
        printf("不在范围内!");
    }
    return 0;
}
int Char2Hex(char fromc,int *toi)
{
 if(fromc>='0'&& fromc<='9')
 {
             *toi= fromc-'0';
 }
 else if(fromc>='A'&& fromc<='F')
 {
             *toi= fromc-'A'+10;
 
        }
        else{
             printf("不在范围内");
        }
 return 0;
}

//utils.h
#ifndef UTILS_H
#define UTILS_H

int Hex2Char(int fromi,char *toc);//16进制数转换成16进制的字符；
int Char2Hex(char fromc,int *toi);//16进制的字符转化成16进制数；

#endif

//test.c
#include<stdio.h>
#include"utils.h"
int main(){

  unsigned char * c;
  Hex2Char(1, &c);
  printf("result=%c\n",c);
  Hex2Char(15, &c);
  printf("result=%c\n",c);
  Hex2Char(11, &c);
  printf("result=%c\n",c);
  unsigned int i;
  Char2Hex('1', &i);
  printf("result=%d\n",i);
  Char2Hex('F', &i);
  printf("result=%d\n",i);
  Char2Hex('D', &i);
  printf("result=%d\n",i);
  return 0;
}