摘要： coded by 老鱼from itertools import combinations, productdef func(numbers, m, s): def determinate(args): return sum(args) == s return filter(determinate, product(numbers, repeat = m))print(func(range(10), 2, 5))输出: [(0, 5), (1, 4), (2, 3), (3, 2), (4, 1), (5, 0)]【 在 wenti (question) 的大作中提到: 】: n个数，任取m个 阅读全文