coded by 老鱼
from itertools import combinations, product
def func(numbers, m, s):
def determinate(args):
return sum(args) == s
return filter(determinate, product(numbers, repeat = m))
print(func(range(10), 2, 5))
输出:
[(0, 5), (1, 4), (2, 3), (3, 2), (4, 1), (5, 0)]
【 在 wenti (question) 的大作中提到: 】
: n个数，任取m个，使得和为s
: m不定，可重复取
