python改XML 

 1 from lxml import etree
 2 import os
 3 
 4 
 5 # 查询文件夹中所有的xml文件，存到xml_files中
 6 def findXmlFile(filePath):
 7     xml_files =[]
 8     for root, folder, files in os.walk(filePath):
 9         for file in files:
10             if file.endswith('.xml'):
11                 xml_files.append(os.path.join(root, file))
12     return xml_files
13 
14 
15 
16 #模糊匹配目录xml文件名，符合条件的文件存到target_file列表中
17 def fuzzyfinder(user_input, xml_files):
18     target_file =[]
19     for xml_file in xml_files:  # 遍历文件夹中的文件，i：'d:\\xml\\LiveCheck_Provider_HttpRS1.xml'
20         if xml_file.find(user_input) > 0:
21             target_file.append(xml_file)
22     return target_file
23 
24 
25 #查找要替换的目标元素
26 def findByXpath(target_file,target_filed):
27     #循环查找遍历xml文件
28     ret = []
29     elementName = []
30     for path in target_file:
31         xml = etree.parse(path, etree.HTMLParser()) #利用lxml解析库的 etree.parse方法
32         target_filed_lower = target_filed.lower()  # 转换为小写
33         command = '//@' + target_filed_lower  # 目标字段转成：//@rateplancode
34         result = xml.xpath(command)  # 用xpath找到目标，结果是list,如有RatePlanCode="DSRPLO01",RatePlanCode="DSRPLO02"，用//@rateplancode找到的值是：['DSRPLO01', 'DSRPLO02']
35         fileName = "文件名:" + os.path.basename(path)  # 获取文件名,如：文件名:LiveCheck_P1rovider_HttpRS.xml
36         print fileName
37         for i in range(len(result)):  # 遍历xpath查到的结果
38             str = target_filed + '="' + result[i] + '"'  # 把字段和结果拼接起来,RatePlanCode="DSRPLO01",RatePlanCode="DSRPLO02"
39             elementName.append(str)  # 拼接结果放到列表
40         print(elementName)
41         ret.append(elementName)
42         elementName = []
43 
44 def my_Replace(content, target_filed, new_filed, index=0):
45     # 替换成修改的数据
46     print target_filed, new_filed, index
47     str = content.replace(target_filed, new_filed, int(index))
48     # 把前面被替换的数据修改回来
49     a = int(index) - 1
50     ret = str.replace(new_filed, target_filed, a)
51     return ret
52 
53 def writeXML(target_file,target_filed,new_filed,index):
54     # 替换内容并写入文件
55     for path in target_file:
56         with open(path, "r") as file:
57             fullcontent = file.read()#获取文件所有内容
58         if len(index) == 0:
59             content = fullcontent.replace(target_filed,new_filed)
60         else:
61             content = my_Replace(fullcontent,target_filed,new_filed,index)
62         f = open(path, 'w')
63         f.write(content)
64         f.close()
65 
66 
67 if __name__ == '__main__':
68     xml_files =[]
69     elementNames=[]
70     #遍历文件夹中xml的数量
71     xml_files = findXmlFile("D:/xml")
72     if len(xml_files):
73         print("文件夹中所有XML文件:")
74         print(xml_files)
75         user_input = raw_input("请输入需要修改的文件名(大小写敏感):")
76         target_file = fuzzyfinder(user_input,xml_files)
77         if len(target_file):
78             print("匹配到的XML文件:")
79             print target_file
80             target_filed = raw_input("输入需要查询的元素: ")
81             while(1):
82                 findByXpath(target_file, target_filed)
83                 old = raw_input("输入需要修改原内容:")
84                 new = raw_input("输入需要修改后的内容:")
85                 i = raw_input("输入需要修改的下标:")
86                 if old == '':
87                     break
88                 else:
89                     writeXML(target_file,old,new,i)
90         else:
91             print ("没有匹配到XML文件")
92     else:
93         print("文件夹中不存在XML文件:")

 

posted on 2020-03-08 22:35  fengyelan2233  阅读(217)  评论(0)  编辑  收藏  举报

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