单片机其他外围设备的使用

蜂鸣器的使用:

蜂鸣器粗略设定频率,以20ms即50hz发声

#include<reg52.h>
#define uint unsigned int
#define uchar unsigned char
sbit fen = P2^6;
void delay(uint z);
main()
{
    while(1)
    {
        delay(1);//延时10毫秒注意这里输出的是20毫秒的方波
                //因为方波要有正负的跳变才能算一个周期,这里?
                //每隔10毫秒跳变一次,因此周期是200ms,频率是50Hz  
        fen = ~fen;
    }
}

void delay(uint z)
{
    uint x,y;
    for(x=z;x>0;x--)
        for(y=110;y>0;y--);
    
}
View Code

蜂鸣器精确控制发声:使用定时器

#include<reg52.h>
#define  uint unsigned int
#define uchar unsigned char
sbit  fen = P2^6;
uchar num,ben;
void init();
void main()
{
    init();
    while(1);

}

void init()
{
    TMOD = 0x11;
    TH1 = (65536-50000)/256;
    TL1 = (65536-50000)%256;
    ET1 = 1;
    EA = 1;
    TR1 =1;
    
}
void time1()interrupt 3
{
    TH1 = (65536-5000)/256;//定时一次是50毫秒
    TL1 = (65536-5000)%256;
    num++;
    if(num==2)
    {
        num = 0;
        fen = ~fen;
    }

}
View Code

 蜂鸣器精确发声(控制其发出100ms,200ms,300ms,400ms,500ms 的频率

错误代码:

//这个程序调试了一上午吧,感觉有点不对劲,问题是出在  
//定时器的打断上,即两个定时器都在工作的时候,会不会打断原来的定时器
//这个程序实习实现的功能本来是使喇叭发声,发出
//以100ms,200,300,400,500
//本来应该听到5个频率,但是实际只是听到3个,说明中断发生了错位,中断之间产生了相互的影响     
#include<reg52.h>
#define  uint unsigned int
#define uchar unsigned char
sbit  fen = P2^6;
uchar num,flag,tt;
void init();
void main()
{
    init();
    while(1);

}

void init()
{
    TMOD = 0x11;
    TH1 = (65536-50000)/256;
    TL1 = (65536-50000)%256;
    TH0 = (65536-50000)/256;
    TL0 = (65536-50000)%256;
    ET1 = 1;
    ET0 =1;
    EA = 1;
    TR0 =1;
    TR1 =1;

    
}
void time0()interrupt 1
{
    TH0 = (65536-50000)/256;
    TL0 = (65536-50000)%256;
    tt++;
    switch(tt/20)
    {
        case 0:
            flag = 1;
            break;
        case 1:
            flag = 2;
            break;
        case 2:
            flag = 3;
            break;
        case 3:
            flag = 4;
            break;
        case 4:
            tt=0;
            flag = 5;
            break;
    }
}

void time1()interrupt 3
{
    TH1 = (65536-5000)/256;//定时一次是50毫秒
    TL1 = (65536-5000)%256;
    num++;
    if(num==flag)
    {
        num = 0;
        fen = ~fen;
    }

}
View Code

 正确代码

/*                                                          
同时用两个定时器控制蜂鸣器发声,  
定时器0控制频率,定时器1控制同个   
频率持续的时间,间隔2s依次输出  
1,10,50,100,200,400,800,
1k(hz)的方波?
设晶振频率为12MHz。
*/

#include<reg52.h>
#include<intrins.h>
#define uint unsigned int
#define uchar unsigned char
sbit beep = P2^3;
uchar tt;
uint fre,flag;

void main()
{
    fre = 50000;
    beep = 0;
    TMOD = 0x11;
    TH0 = (65536-fre)/256;
    TL0 = (65536-fre)%256;
    TH1 = (65536- 50000)/256;
    TL1 = (65536-50000)%256;
    EA = 1;
    ET0 = 1;
    ET1 =1;
    TR0 =1;
    TR1 = 1;
    while(1);
}

void timer0()interrupt 1
{
    TR0 = 0;//进入中断函数后关闭定时器0,以防止内部程序中断丢失
    TH0 = (65536-50000)/256;
    TL0 = (65536-50000)%256;
    tt ++;
    if(flag<40)
        if(tt==10)
            {
                tt = 0;
                fre = 50000;//分别用fre来选取频率定时50ms,所以中断产生的频率为10hz
                beep = ~beep;
            }
    if(flag>=40&&flag<80)
        {
            tt = 0;
            fre = 50000;//分别用fre来选取频率定时50ms,所以中断产生的频率为10hz
            beep =~beep;
        }
    if(flag>=80&&flag<120)
        {
            tt = 0;
            fre = 10000;//定时10ms,周期为20ms,频率为50hz 
            beep =~beep;
        }
     if(flag>=120&&flag<160)
        {
            tt = 0;
            fre = 5000;//定时5毫秒,周期为10ms,频率为100zh 
            beep =~beep;
        }
     if(flag>=160&&flag<200)
        {
            tt = 0;
            fre = 2500;//定时2.5,周期5ms,频率为200  
            beep =~beep;
        }
          if(flag>=200&&flag<240)
        {
            tt = 0;
            fre = 1250;//定时1.25,周期2.5ms,频率400 
            beep =~beep;
        }
        if(flag>=240&&flag<280)
        {
            tt = 0;
            fre = 625;//定时2.5,周期5ms,频率为800  
            beep =~beep;
        }
        if(flag>=280&&flag<320)
        {
            tt = 0;
            fre = 312;//频率为1600
            beep =~beep;
        }
        if(flag>=320&&flag<360)
        {
            tt = 0;
            fre = 156;//频率为3200
            beep =~beep;
        }
        TR0 = 1;
        
}

void timer1()interrupt 3
{
        TH1 = (65536 - 50000)/256;
        TL1 = (65536 - 50000)%256;
        flag++;
        if(flag == 360)
        {
            flag = 0;
            fre = 50000;
        }
}
View Code

 

posted @ 2013-10-11 09:02  跨七海的风  阅读(384)  评论(0编辑  收藏  举报