摘要: ###参考链接 #代码块 def dict_factory(cursor, row): d = {} for idx, col in enumerate(cursor.description): d[col[0]] = row[idx] return d con = sqlite3.connect( 阅读全文
posted @ 2022-12-28 15:28 毛绒绒 阅读(157) 评论(0) 推荐(0) 编辑