用struts实现简单的登录
1.建项目时选java EE6.0
2.写登陆界面
<body>
<center>
<form id="form1" name="form1" action="action/login.action" method="post">
用户名<input name="username" type="text"><br>
密码<input name="password" type="password"><br>
<input type="submit" value="登录">
</form>
</center>
</body>
3.右击项目名-->Eclipse-->Add Struts Support-->Struts 2.1-->finish
4.建类login.jsp继承ActionSupport
5.写login.java
ackage com.chao.s4;
import com.opensymphony.xwork2.ActionSupport;
public class login extends ActionSupport {
private String username="";
private String password="";
public String getUsername() {
return username;
}
public void setUsername(String username) {
this.username = username;
}
public String getPassword() {
return password;
}
public void setPassword(String password) {
this.password = password;
}
public String execute() throws Exception {
// TODO Auto-generated method stub
String u,p;
u=getUsername();
p=getPassword();
if(u.equals("1")&&p.equals("1"))
{
return "success";
}
else
return "error";
}
}
6.写struts.xml（可以拖）
代码：
<struts> <package name="default" namespace="/action" extends="struts-default"> <action name="login" class="com.chao.s4.login"> <result name="success">../success.jsp</result> <result name="error">../error.jsp</result> </action> </package> </struts>
7.最后写success.jsp和error.jsp
<body>
登陆成功<a href=index.jsp>返回</a><br>
</body>
<body>
登陆失败<a href=index.jsp>返回</a><br>
</body>
