JS判断两个数是否能除尽
function judgeDivisor(m, n) { var num = {}; var i = 0; var x = parseInt(m / n); m = m % n; var result = ""; while (m != 0 && !(m in num)) { num[m] = i++; result += parseInt(m * 10 / n); m = m * 10 % n; } return m == 0; }
posted on 2020-07-18 00:10 成天吐槽的菜鸡前端 阅读(1151) 评论(0) 编辑 收藏 举报