B - A + B Again

Description

There must be many A + B problems in our HDOJ , now a new one is coming.         Give you two hexadecimal integers , your task is to calculate the sum of them,and print it in hexadecimal too.         Easy ? AC it !       

                

Input

The input contains several test cases, please process to the end of the file.         Each case consists of two hexadecimal integers A and B in a line seperated by a blank.         The length of A and B is less than 15.       

                

Output

For each test case,print the sum of A and B in hexadecimal in one line.        

                

Sample Input

+A -A +1A 12 1A -9 -1A -12 1A -AA

                

Sample Output

0 2C 11 -2C -90

 

 

十六进制两数相加并输出十六进制

定义 __int64  即可    

C语言输入输出十六进制 用 “%X”   输入__int64的十六进制为"%I64X“

所以直接相加减 

但是 电脑储存的数为补码   结果若为正数则无影响  但若为负数  则必须将结果变为正数输出  printf("-%I64X\n",-c);

 

#include<stdio.h>
int main()
{
    __int64 a,b,c;
    char s[100];
    while(scanf("%I64X%I64X",&a,&b)!=EOF)
    {
        c=a+b;
        if(c<0)
        printf("-%I64X\n",-c);
        else
        printf("%I64X\n",c);   
    }
    return 0;
}