获取List<Map<String, Object>中Map的属性值列表,获取所有map对象的某个属性列表
获取List<Map<String, Object>中Map的属性值列表,
获取所有map对象的某个属性列表
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©Copyright 蕃薯耀 2021-06-29
https://www.cnblogs.com/fanshuyao/
/** * 获取List列表中的Map对象属性的值 * @param <T> * @param list List<Map<String, Object>> * @param mapValueName Map对象属性名 * @return * @throws Exception */ @SuppressWarnings("unchecked") public static <T> List<T> getMapValues(List<Map<String, Object>> list, String mapValueName) throws Exception{ log.info("mapValueName = " + mapValueName); if(StringUtils.isBlank(mapValueName)) { throw new ValidationException("Map对象属性名不能为空"); } List<T> objectidList = new ArrayList<T>(); for (Map<String, Object> map : list) { objectidList.add((T) map.get(mapValueName)); } return objectidList; }
Main方法
public static void main(String[] args) throws Exception { List<Map<String, Object>> list = new ArrayList<Map<String,Object>>(); Map<String, Object> map1 = new HashMap<String, Object>(); map1.put("name", "aa"); map1.put("age", 25); map1.put("long", 10000000000L); map1.put("double", 10000.25d); Map<String, Object> map2 = new HashMap<String, Object>(); map2.put("name", "bb"); map2.put("age", 24); map2.put("long", 20000000000L); map2.put("double", 20000.25d); Map<String, Object> map3= new HashMap<String, Object>(); map3.put("name", "cc"); map3.put("age", 26); map3.put("long", 30000000000L); map3.put("double", 30000.25d); list.add(map1); list.add(map2); list.add(map3); List<String> listResult = getMapValues(list, "name"); System.out.println(listResult); List<Integer> listAge = getMapValues(list, "age"); System.out.println(listAge); List<Long> listLong = getMapValues(list, "long"); System.out.println(listLong); List<Long> listDouble = getMapValues(list, "double"); System.out.println(listDouble); }
输出结果:
mapValueName = name [aa, bb, cc] mapValueName = age [25, 24, 26] mapValueName = long [10000000000, 20000000000, 30000000000] mapValueName = double [10000.25, 20000.25, 30000.25]
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©Copyright 蕃薯耀 2021-06-29
https://www.cnblogs.com/fanshuyao/
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