Cylinder

http://acm.sdut.edu.cn/sdutoj/problem.php?action=showproblem&problemid=2374

思路:三分枚举。

 1 #include <cstdio>
 2 #include <cmath>
 3 #include <cstring>
 4 #include <algorithm>
 5 #define maxn 1000100
 6 using namespace std;
 7 const double eps=1e-12;
 8 const double pi=acos(-1.0);
 9 
10 double w,h;
11 
12 double ok(double x,int flag)
13 {
14     double max1=0;
15     double k=h;
16     double s=w;
17     double r=(x>s)?s:x;
18     double ss=pi*(r/2)*(r/2);
19     double ll=pi*r;
20     double c=k-x;
21     double r1=(k-x)>s?s:(k-x);
22     if(s>=ll&&flag==1)
23     {
24         double v1=ss*c;
25         max1=max(max1,v1);
26     }
27     if(c>=ll&&flag==2)
28     {
29         double v2=ss*s;
30         max1=max(max1,v2);
31     }
32     double s1=pi*(r1/2)*(r1/2);
33     double l1=pi*r1;
34     if(s>=l1&&flag==1)
35     {
36         double v3=s1*x;
37         max1=max(v3,max1);
38     }
39     if(x>=l1&&flag==2)
40     {
41         double v4=s1*s;
42         max1=max(max1,v4);
43     }
44     return max1;
45 }
46 
47 
48 int main()
49 {
50     while(scanf("%lf%lf",&w,&h)!=EOF)
51     {
52         if(w==0&&h==0) break;
53         double l=0,r=h;
54         double ans=0,ans1=0;
55         while(r-l>eps)
56         {
57             double mid1=(r+l)/2;
58             double mid2=(l+mid1)/2;
59             if(ok(mid1,1)>=ok(mid2,1))
60             {
61                 ans=mid1;
62                 l=mid2;
63             }
64             else
65                 r=mid1;
66         }
67         l=0,r=w;
68         while(r-l>eps)
69         {
70             double mid1=(r+l)/2;
71             double mid2=(l+mid1)/2;
72             if(ok(mid1,2)>=ok(mid2,2))
73             {
74                 ans1=mid1;
75                 l=mid2;
76             }
77             else
78                 r=mid1;
79         }
80         printf("%.3lf\n",max(ok(ans,1),ok(ans1,2)));
81     }
82     return 0;
83 }
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posted @ 2015-02-01 16:35  null1019  阅读(168)  评论(0编辑  收藏  举报