SQL Server 中master..spt_values的应用
select number from master..spt_values with(nolock) where type='P'
/**解释:master..spt_values表的字段值为P的对应number字段值是从0-2047*/
--1.将字符串转换为列显示
if object_id('tb') is not null drop table tb
go
create table tb([编号] varchar(3),[产品] varchar(2),[数量] int,[单价] int,[金额] int,[序列号] varchar(8))
insert into tb([编号],[产品],[数量],[单价],[金额],[序列号])
select '001','AA',3,5,15,'12,13,14' union all
select '002','BB',8,9,13,'22,23,24'
go
select [编号],[产品],[数量],[单价],[金额]
,substring([序列号],b.number,charindex(',',[序列号]+',',b.number)-b.number) as [序列号]
from tb a with(nolock),master..spt_values b with(nolock)
where b.number>=1 and b.number=1 and number<=len(@str+',') and type='P'
and substring(@str+',',number,1)=','
)select ss from cte where xh=4
/**
ss
-------------------
10,102,10254,103265
*/
----------
--3.找出两句话中相同的汉字
declare @Lctext1 varchar(100)
declare @Lctext2 varchar(100)
set @Lctext1='我们都是来自五湖四海的朋友'
set @Lctext2='朋友多了路真的好走吗'
select substring(@Lctext2,number,1) as value
from master..spt_values with(nolock)
where type='P' and number>=1 and number<=len(@Lctext2)
and charindex(substring(@Lctext2,number,1),@Lctext1,number)>1
/**
value
-----
朋
友
的
*/
---------
--4.提取两个日期之间的所有月份
if object_id('tb') is not null drop table tb
go
create table tb(id int identity(1,1),startDate varchar(10),endDate varchar(10))
insert into tb(startDate,endDate) select '2013-01-01','2013-09-25'
go
declare @startDate varchar(10)
declare @endDate varchar(10)
select @startDate=startDate,@endDate=endDate from tb with(nolock)
select convert(varchar(7),dateadd(mm,number,@startDate),120) as [月份]
from master..spt_values with(nolock)
where type='P' and number>=0
and dateadd(mm,number,@startDate)<=@endDate
go
drop table tb
go
/**
月份
-------
2013-01
2013-02
2013-03
2013-04
2013-05
2013-06
2013-07
2013-08
2013-09
*/
---------
--5.求一个日期所在月份的所有日期
declare @date datetime
set @date='2013-08-31'
select convert(char(7),@date,120)+'-'+right('0'+convert(varchar(2),number),2) as [日期格式1]
,ltrim(year(@date))+right(100+month(@date),2)+right('0'+ltrim(number),2) as [日期格式2]
from master..spt_values with(nolock)
where type='P' and number>=1
--and number<=datediff(dd,@date,dateadd(mm,1,@date)) --对于mssql而言该语句不试用于2013-08-31的情况，这时由于9月没有31号，固计算出来的天数是30天
and number<=datediff(dd,convert(char(7),@date,120)+'-01',convert(char(7),dateadd(mm,1,@date),120)+'-01')--转换为1号来计算天数
/**
日期格式1 日期格式2
----------- --------------------
2013-08-01 20130801
2013-08-02 20130802
2013-08-03 20130803
2013-08-04 20130804
2013-08-05 20130805
2013-08-06 20130806
2013-08-07 20130807
2013-08-08 20130808
2013-08-09 20130809
2013-08-10 20130810
2013-08-11 20130811
2013-08-12 20130812
2013-08-13 20130813
2013-08-14 20130814
2013-08-15 20130815
2013-08-16 20130816
2013-08-17 20130817
2013-08-18 20130818
2013-08-19 20130819
2013-08-20 20130820
2013-08-21 20130821
2013-08-22 20130822
2013-08-23 20130823
2013-08-24 20130824
2013-08-25 20130825
2013-08-26 20130826
2013-08-27 20130827
2013-08-28 20130828
2013-08-29 20130829
2013-08-30 20130830
2013-08-31 20130831
*/
---------
--6.根据给定时间为基准以2小时为划分，得出一天划分出的时间段
declare @time varchar(5)
set @time='11:13'
select ltrim(a.number)+right(@time,3)+'-'+ltrim(b.number)+right(@time,3) as [划分结果]
from master..spt_values a with(nolock),master..spt_values b with(nolock)
where a.type='P' and b.type='P'
and a.number>=left(@time,2) and b.number<=24
and a.number+2=b.number
/**
划分结果
-----------------------------------
11:13-13:13
12:13-14:13
13:13-15:13
14:13-16:13
15:13-17:13
16:13-18:13
17:13-19:13
18:13-20:13
19:13-21:13
20:13-22:13
21:13-23:13
22:13-24:13
*/
---------
--7.将字符串显示为行列
if object_id('tb') is not null drop table tb
create table tb(id int identity(1,1),s nvarchar(100))
insert into tb(s) select '车位地址1,车位状况1|车位地址2,车位状况2|车位地址n,车位状况n'
;with cte as(
select substring(s,number,charindex('|',s+'|',number)-number) as ss
from tb with(nolock),master..spt_values with(nolock)
where type='P' and number>=1 and number<=len(s)
and substring('|'+s,number,1)='|'
)select left(ss,charindex(',',ss)-1)as s1,substring(ss,charindex(',',ss)+1,len(ss))as s2 from cte
drop table tb
/**
s1 s2
----------- ------------
车位地址1 车位状况1
车位地址2 车位状况2
车位地址n 车位状况n
*/
