【POJ 2406】 Power Strings
【题目链接】
【算法】
KMP
如果字符串中存在循环节,则next[len] = (循环节个数 - 1) * 循环节长度
循环节个数 = len / (len - next[len])
【代码】
#include <algorithm> #include <bitset> #include <cctype> #include <cerrno> #include <clocale> #include <cmath> #include <complex> #include <cstdio> #include <cstdlib> #include <cstring> #include <ctime> #include <deque> #include <exception> #include <fstream> #include <functional> #include <limits> #include <list> #include <map> #include <iomanip> #include <ios> #include <iosfwd> #include <iostream> #include <istream> #include <ostream> #include <queue> #include <set> #include <sstream> #include <stdexcept> #include <streambuf> #include <string> #include <utility> #include <vector> #include <cwchar> #include <cwctype> #include <stack> #include <limits.h> using namespace std; #define MAXL 10000010 int len; char s[MAXL]; int next[MAXL]; template <typename T> inline void read(T &x) { int f = 1; x = 0; char c = getchar(); for (; !isdigit(c); c = getchar()) { if (c == '-') f = -f; } for (; isdigit(c); c = getchar()) x = (x << 3) + (x << 1) + c - '0'; x *= f; } template <typename T> inline void write(T x) { if (x < 0) { putchar('-'); x = -x; } if (x > 9) write(x/10); putchar(x%10+'0'); } template <typename T> inline void writeln(T x) { write(x); puts(""); } inline void getnext() { int i,pos; next[1] = 0; for (i = 2; i <= len; i++) { pos = next[i-1]; while (pos > 0 && s[pos+1] != s[i]) pos = next[pos]; if (s[i] == s[pos+1]) next[i] = pos + 1; else next[i] = 0; } } int main() { while (true) { scanf("%s",s+1); if (s[1] == '.') return 0; len = strlen(s+1); getnext(); if (len % (len - next[len]) == 0) writeln(len/(len-next[len])); else writeln(1); } return 0; }