C#实现的对文件的重命名
如下C#实现对文件的重命名的方法需要传入三个string类型的参数,分别是源文件的文件目录、目的文件目录和重命名的文件名称,实现代码如下:
public ExecutionResult FileRename(string sourceFile, string destinationPath, string destinationFileName) { ExecutionResult result; FileInfo tempFileInfo; FileInfo tempBakFileInfo; DirectoryInfo tempDirectoryInfo; result = new ExecutionResult(); tempFileInfo = new FileInfo(sourceFile); tempDirectoryInfo = new DirectoryInfo(destinationPath); tempBakFileInfo = new FileInfo(destinationPath + "\\" + destinationFileName); try { if (!tempDirectoryInfo.Exists) tempDirectoryInfo.Create(); if (tempBakFileInfo.Exists) tempBakFileInfo.Delete(); //move file to bak tempFileInfo.MoveTo(destinationPath + "\\" + destinationFileName); result.Status = true; result.Message = "Rename file OK"; result.Anything = "OK"; } catch (Exception ex) { result.Status = false; result.Anything = "Mail"; result.Message = ex.Message; if (mesLog.IsErrorEnabled) { mesLog.Error(MethodBase.GetCurrentMethod().Name, "Rename file error. Msg :" + ex.Message); mesLog.Error(ex.StackTrace); } } return result; }