离散数学学习笔记-01-基础知识
集合与序列
集合的基本概念
集合set:大写字母表示S
集合的元素:小写字母表示a,
a
∈
S
a \in S
a∈S
集合的特点:
- 能够明确的判断一个元素是或不是属于某集合
- 集合的元素没有顺序
- 集合的元素之间不一定存在什么关系
- 规定:对任意集合A都有 A ∉ A A \notin A A∈/A
特殊集合:
自然数:N,整数:Z,正整数:
Z
+
Z^+
Z+,非零整数集
Z
∗
Z^*
Z∗,有理数集
Q
Q
Q,非零有理数集
Q
∗
Q^*
Q∗,实数
R
R
R,非零实数集
R
∗
R^*
R∗,复数
C
C
C
集合的表示:
- 外延表示法(列举法) { ⋯ } \{\cdots\} {⋯}
- 内涵表示法(描述法) { x ∣ P ( x ) } \{x|P(x)\} {x∣P(x)}
子集和超集:
A
⊆
B
A \subseteq B
A⊆B
A
=
B
:
A
⊆
B
a
n
d
B
⊆
A
A = B:A \subseteq B\ and\ B \subseteq A
A=B:A⊆B and B⊆A
全集:
U
U
U
空集:
∅
\emptyset
∅
基数、势cardinality:集合中的元素数
∣
A
∣
,
#
A
,
c
a
r
d
(
A
)
|A|, \#A, card(A)
∣A∣,#A,card(A)
幂集(power set):A的所有子集所组成的集合,
∮
(
A
)
=
{
x
∣
x
⊂
A
}
\oint(A) = \{x|x \subset A\}
∮(A)={x∣x⊂A}其中有空集和A本身
证明
X
⊆
Y
X \subseteq Y
X⊆Y的基本方法是:对于任意的
x
∈
X
x \in X
x∈X,有
x
∈
Y
x \in Y
x∈Y
证明两个集合相等的方法是分别证明
X
⊆
Y
a
n
d
Y
⊆
X
X \subseteq Y \ and\ Y \subseteq X
X⊆Y and Y⊆X
集合的运算
- 交集 A ⋂ B , i n t e r s e c t i o n A \bigcap B, intersection A⋂B,intersection
- 并集 A ⋃ B , u n i o n A \bigcup B, union A⋃B,union
- B关于A的相对补(complement of B with respect to A)或A与B的差集(difference): A − B = A B ‾ A - B=A\overline{B} A−B=AB
- 补集 A ‾ , ∼ A , c o m p l e m e n t \overline{A},\sim A, complement A,∼A,complement,A关于U的相对补
- 对称差 A ⨁ B = { x ∣ x ∈ A o r x ∈ B a n d x ∉ A ⋂ B = ( A − B ) ⋃ ( B − A ) , s y m m e t r i c d i f f e r e n c e A\bigoplus B = \{x|x \in A\ or\ x \in B\ and\ x \notin A\bigcap B = (A - B) \bigcup (B - A), symmetric\ difference A⨁B={x∣x∈A or x∈B and x∈/A⋂B=(A−B)⋃(B−A),symmetric difference
集合运算的性质
- 交换律:
A ⋃ B = B ⋃ A A ⋂ B = B ⋂ A A ⨁ B = B ⨁ A A \bigcup B = B \bigcup A \\ A \bigcap B = B \bigcap A \\ A \bigoplus B = B \bigoplus A A⋃B=B⋃AA⋂B=B⋂AA⨁B=B⨁A - 结合律:
( A ⋃ B ) ⋃ C = A ⋃ ( B ⋃ C ) ( A ⋂ B ) ⋂ C = A ⋂ ( B ⋂ C ) ( A ⨁ B ) ⨁ C = A ⨁ ( B ⨁ C ) (A \bigcup B) \bigcup C = A \bigcup (B \bigcup C) \\ (A \bigcap B) \bigcap C = A \bigcap (B \bigcap C) \\ (A \bigoplus B) \bigoplus C = A \bigoplus (B \bigoplus C) (A⋃B)⋃C=A⋃(B⋃C)(A⋂B)⋂C=A⋂(B⋂C)(A⨁B)⨁C=A⨁(B⨁C) - 分配率:
A ⋃ ( B ⋂ C ) = ( A ⋃ B ) ⋂ ( A ⋃ C ) A ⋂ ( B ⋃ C ) = ( A ⋂ B ) ⋃ ( A ⋂ C ) A \bigcup (B \bigcap C) = (A \bigcup B) \bigcap ( A \bigcup C) \\ A \bigcap (B \bigcup C) = (A \bigcap B) \bigcup ( A \bigcap C) A⋃(B⋂C)=(A⋃B)⋂(A⋃C)A⋂(B⋃C)=(A⋂B)⋃(A⋂C) - 吸收率:
A ⋃ ( A ⋂ B ) = A A ⋂ ( A ⋃ B ) = A A \bigcup (A \bigcap B) = A \\ A \bigcap ( A \bigcup B) = A A⋃(A⋂B)=AA⋂(A⋃B)=A - 德摩根律:
绝对形式:
A ⋃ B ‾ = A ‾ ⋂ B ‾ A ⋂ B ‾ = A ‾ ⋃ B ‾ \overline{A \bigcup B} = \overline{A} \bigcap \overline{B} \\ \overline{A \bigcap B} = \overline{A} \bigcup \overline{B} A⋃B=A⋂BA⋂B=A⋃B
相对形式:
A − ( B ⋃ C ) = ( A − B ) ⋂ ( A − C ) A − ( B ⋂ C ) = ( A − B ) ⋃ ( A − C ) A - (B \bigcup C) = (A - B) \bigcap (A - C) \\ A - (B \bigcap C) = (A - B) \bigcup (A - C) A−(B⋃C)=(A−B)⋂(A−C)A−(B⋂C)=(A−B)⋃(A−C) - 幂等律:
A ⋂ A = A A ⋃ A = A A \bigcap A = A \\ A \bigcup A = A A⋂A=AA⋃A=A - 零律:
A ⋃ U = U A ⋂ ∅ = ∅ A \bigcup U = U\\ A \bigcap \emptyset = \emptyset A⋃U=UA⋂∅=∅ - 同一律:
A ⋂ U = A A ⋃ ∅ = A A \bigcap U = A \\ A \bigcup \emptyset = A A⋂U=AA⋃∅=A - 排中律:
A ⋃ A ‾ = U A \bigcup \overline{A} = U A⋃A=U - 矛盾律:
A ⋂ A ‾ = ∅ A \bigcap \overline{A} = \emptyset A⋂A=∅
序列的基本概念
- sequence:排成一列的对象,有顺序,里面的对象为项item;
- 对于给定的集合A, A ∗ A^* A∗为所有由A种元素生成的有限长度序列全体, A ∗ A^* A∗中的元素称为A上的词word或串string;
- 假设 A = { a , b , c , ⋯ , z } A = \{a,b,c,\cdots,z\} A={a,b,c,⋯,z},则 A ∗ A^* A∗中包括的为若干单词, A ∗ A^* A∗中的空序列称作空串empty string,记作 λ , ε \lambda,\varepsilon λ,ε;
- 假设A是集合, w 1 = s 1 s 2 ⋯ s n , w 2 = t 1 t 2 ⋯ t n w_1 = s_1s_2\cdots s_n,w_2 = t_1t_2\cdots t_n w1=s1s2⋯sn,w2=t1t2⋯tn都是 A ∗ A^* A∗中的元素,则 w 1 , w 2 w_1,w_2 w1,w2的连接catenation为 s 1 s 2 ⋯ s n t 1 t 2 ⋯ t n s_1s_2\cdots s_nt_1t_2\cdots t_n s1s2⋯snt1t2⋯tn记作 w 1 ∘ w 2 w_1 \circ w_2 w1∘w2
布尔矩阵
布尔矩阵boolean matrix,位矩阵bit matrix
- A = [ a i j ] A = [a_{ij}] A=[aij]是一个 m × n m \times n m×n的布尔矩阵,则定义其补complement为 A ‾ = [ a i j ‾ ] = [ 1 − a i j ] \overline{A} = [\overline{a_{ij}}] = [1- a_{ij}] A=[aij]=[1−aij]
-
A
=
[
a
i
j
]
A = [a_{ij}]
A=[aij]和
B
=
[
b
i
j
]
B = [b_{ij}]
B=[bij]都是
m
×
n
m \times n
m×n的布尔矩阵
A ⋂ B A ⋃ B A \bigcap B \\ A \bigcup B A⋂BA⋃B -
A
=
[
a
i
j
]
A = [a_{ij}]
A=[aij]是
m
×
n
m \times n
m×n矩阵,
B
=
[
b
i
j
]
B = [b_{ij}]
B=[bij]是
n
×
r
n \times r
n×r矩阵,布尔积boolean product,
A
⊙
B
=
C
=
[
c
i
j
]
A \odot B = C = [c_{ij}]
A⊙B=C=[cij]
c i j = { 1 若存在 k , 1 ≤ k ≤ n 使得 a i k = 1 且 b k j = 1 0 o t h e r w i s e c_{ij} = cij={10若存在k,1≤k≤n使得aik=1且bkj=1otherwise - 定理:
A ⋃ B = C = [ c i j ] c i j = a i j + b i j − a i j b i j A ⋂ B = D = [ d i j ] d i j = a i j b i j A \bigcup B = C = [c_{ij}] \ c_{ij} = a_{ij} + b_{ij} - a_{ij}b_{ij} \\ A \bigcap B = D = [d_{ij}] \ d_{ij} = a_{ij}b_{ij} A⋃B=C=[cij] cij=aij+bij−aijbijA⋂B=D=[dij] dij=aijbij - 交换律:
A ⋂ B = B ⋂ A A ⋃ B = B ⋃ A A \bigcap B = B \bigcap A \\ A \bigcup B = B \bigcup A A⋂B=B⋂AA⋃B=B⋃A - 结合律:
( A ⋃ B ) ⋃ C = A ⋃ ( B ⋃ C ) ( A ⋂ B ) ⋂ C = A ⋂ ( B ⋂ C ) ( A ⊙ B ) ⊙ C = A ⊙ ( B ⊙ C ) (A \bigcup B) \bigcup C = A \bigcup (B \bigcup C) \\ (A \bigcap B) \bigcap C = A \bigcap (B \bigcap C) \\ (A \odot B) \odot C = A \odot (B \odot C) (A⋃B)⋃C=A⋃(B⋃C)(A⋂B)⋂C=A⋂(B⋂C)(A⊙B)⊙C=A⊙(B⊙C) - 分配率:
A ⋂ ( B ⋃ C ) = ( A ⋂ B ) ⋃ ( A ⋂ C ) A ⋃ ( B ⋂ C ) = ( A ⋃ B ) ⋂ ( A ⋃ C ) ( A ⋃ B ) T = A T ⋃ B T ( A ⋂ B ) T = A T ⋂ B T ( A ⊙ B ) T = B T ⊙ A T A \bigcap (B \bigcup C) = (A \bigcap B) \bigcup (A \bigcap C) \\ A \bigcup (B \bigcap C) = (A \bigcup B) \bigcap (A \bigcup C) \\ (A \bigcup B)^T = A^T \bigcup B^T \\ (A \bigcap B)^T = A^T \bigcap B^T \\ (A \odot B)^T = B^T \odot A^T \\ A⋂(B⋃C)=(A⋂B)⋃(A⋂C)A⋃(B⋂C)=(A⋃B)⋂(A⋃C)(A⋃B)T=AT⋃BT(A⋂B)T=AT⋂BT(A⊙B)T=BT⊙AT
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