Search in Rotated Sorted Array II

Follow up for "Search in Rotated Sorted Array":
What if duplicates are allowed?

Would this affect the run-time complexity? How and why?

Write a function to determine if a given target is in the array.

class Solution {
public:
    bool search(int A[], int n, int target) {
        if(n==0return false;
        
        return binary(A,0,n-1,target);
    }
    bool binary(int A[],int x1,int x2,int target)
    {
        if(x1>x2) return false;
        
        int m=(x1+x2)/2;
        if(A[m]==target) return true;
        if(A[x1]<A[x2])
        {
            if(A[m]<target) return binary(A,m+1,x2,target);
            else return binary(A,x1,m-1,target);
        }
        else
        {
            return binary(A,x1,m-1,target) || binary(A,m+1,x2,target);
        }
    }
}; 
posted @ 2014-05-29 16:54  erictanghu  阅读(71)  评论(0编辑  收藏  举报