Combination Sum

Given a set of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T.

The same repeated number may be chosen from C unlimited number of times.

Note:

  • All numbers (including target) will be positive integers.
  • Elements in a combination (a1a2, … , ak) must be in non-descending order. (ie, a1 ≤ a2 ≤ … ≤ ak).
  • The solution set must not contain duplicate combinations.

For example, given candidate set 2,3,6,7 and target 7
A solution set is: 
[7] 
[2, 2, 3] 

class Solution {
public:
    vector<vector<int> > combinationSum(vector<int> &candidates, int target) 
    {
        //sort candidates
        int size=candidates.size();
        for(int i=0;i<size;i++)
            for(int j=i+1;j<size;j++)
                if(candidates[i]>candidates[j])
                {
                    int tmp=candidates[i];
                    candidates[i]=candidates[j];
                    candidates[j]=tmp;
                }
        //dfs
        vector<vector<int>> result;
        if(size==0return result;
        
        int v[target/candidates[0]];
        int cdep=0;
        int vdep=0;
        dfs(result,candidates,size,v,cdep,vdep,target);
        return result;
    }
    
    void dfs(vector<vector<int>>& result,vector<int> &candidates,int& csize,int* v,int& cdep,int& vdep,int& target)
    {
        if(target==0)
        {
            vector<int> vals;
            for(int i=0;i<vdep;i++)
                vals.push_back(v[i]);
            result.push_back(vals);
            return;
        }
        if(cdep==csize || target<candidates[cdep]) return;
        
        int dup=target/candidates[cdep];
        for(int i=0;i<=dup;i++)
        {
            //add to v
            for(int j=0;j<i;j++) v[vdep+j]=candidates[cdep];
            //search next candidate
            target=target-i*candidates[cdep];
            cdep=cdep+1;
            vdep=vdep+i;
            dfs(result,candidates,csize,v,cdep,vdep,target);
            vdep=vdep-i;
            cdep=cdep-1;
            target=target+i*candidates[cdep];
        }
    }
}; 
posted @ 2014-05-29 16:09  erictanghu  阅读(265)  评论(0编辑  收藏  举报