Generate Parentheses
Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses.
For example, given n = 3, a solution set is:
"((()))", "(()())", "(())()", "()(())", "()()()"
class Solution {
public:
vector<string> generateParenthesis(int n) {
string s;
for(int i=0;i<n*2;i++) s=s+" ";
vector<string> result;
int left=n;
int right=n;
gen(result,s,left,right,0);
return result;
}
void gen(vector<string>& result,string& s,int left,int right,int step)
{
if(left>right) return;
if(left==0 && right==0)
{
result.push_back(s);
return;
}
if(left>0)
{
s[step]='(';
gen(result,s,left-1,right,step+1);
}
if(right>0)
{
s[step]=')';
gen(result,s,left,right-1,step+1);
}
}
};
public:
vector<string> generateParenthesis(int n) {
string s;
for(int i=0;i<n*2;i++) s=s+" ";
vector<string> result;
int left=n;
int right=n;
gen(result,s,left,right,0);
return result;
}
void gen(vector<string>& result,string& s,int left,int right,int step)
{
if(left>right) return;
if(left==0 && right==0)
{
result.push_back(s);
return;
}
if(left>0)
{
s[step]='(';
gen(result,s,left-1,right,step+1);
}
if(right>0)
{
s[step]=')';
gen(result,s,left,right-1,step+1);
}
}
};