ajax 请求常用写法
一、jquery.ajax()
function checkSubmit() { var formData = new FormData($('#ImportForm')[0]);//Form表单数据 url = '@Url.Action("ImportQuestionExcel","Common")' + "?time=" + new Date(); console.log(url); $.ajax({ type:"POST", url:url, data: formData, processData: false,//不处理数据 contentType: false,//不定义类型 因为上传了文件 success:function(data){ Import_OnSuccess(data); }, error:function(){ $(document).alertmsg('confirm',"处理异常"); } }); }
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title></title>
<script type="text/javascript">
var xmlhttp = createXHR();
function createXHR() {
var xhr;
if (window.XMLHttpRequest) {
xhr = new XMLHttpRequest();
} else {
xhr = new ActiveXObject("Microsoft.XMLHTTP");
}
return xhr;
}
function login() {
var span = document.getElementById("msg");
span.innerHTML = "正在登录...";
var name = document.getElementById("txtName").value;
var pwd = document.getElementById("txtPwd").value;
var postData = "n=" + name + "&p=" + pwd;
xmlhttp.open("post", "02-post.ashx", true);
//!!!!!!!!!!!!!!!!!!!post请求,必须设置Content-Type
xmlhttp.setRequestHeader("Content-Type", "application/x-www-form-urlencoded");
xmlhttp.onreadystatechange = function () {
if (xmlhttp.readyState == 4) {
if (xmlhttp.status == 200) {
var r = xmlhttp.responseText;
if (r == 1) {
span.innerHTML = "登录成功";
} else if (r == 0) {
span.innerHTML = "登录失败";
} else {
span.innerHTML = "未知错误";
}
}
else {
span.innerHTML = "服务器内部错误";
}
}
}
xmlhttp.send(postData);
}
</script>
</head>
<body>
用户名:<input type="text" id="txtName" /><br />
密码:<input type="text" id="txtPwd" /><br />
<input type="button" id="btnLogin" value="Login" onclick="login()" /><span style="color:Red" id="msg"></span>
</body>
</html>